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elena55 [62]
3 years ago
9

Which two statements are true about energy transformations?

Physics
2 answers:
Ghella [55]3 years ago
5 0
Energy is never created and energy never is destroyed
krok68 [10]3 years ago
5 0

Explanation:

The process in which energy gets transferred from one form of energy to another is called energy transformations. This process also defines the law of conservation of energy.          

"Energy is neither be created nor be destroyed" is explained by the law of conservation of energy. It only changes one form of energy to another.

There are many forms of energy i.e. electrical energy, mechanical energy, electromagnetic energy, sound energy etc.

The example of energy transformation is best explained by a roller coaster. At the top of a big hill, there exists only kinetic energy. As it descent the hill, the kinetic energy is converted to gravitational potential energy.

Hence, the correct options are (c) Energy is never created. and (e) Energy is never destroyed.

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In this problem, you will use your prior knowledge to derive one of the most important relationships in mechanics: the work-ener
Leya [2.2K]

Answer:

Explanation:

a )

Work done by force = change in kinetic energy

F x s =  ( vf² - vi² ) / 2m

F =  ( vf² - vi² ) / 2ms

acceleration = ( vf² - vi² ) / 2m²s

b )

F = ( vf² - vi² ) / 2ms [ calculated above ]

c )

Work done by force

= change in kinetic energy

= ( vf² - vi² ) / 2m

4 0
3 years ago
Which is an indication that a chemical change to a substance has occurred? A. It changes shape. B. New substances are formed. C.
Levart [38]

Answer:

The answer would be D.

Explanation:

Seven Things That Indicate a Chemical Change Is Occurring

   Gas Bubbles Appear. Gas bubbles appear after a chemical reaction has occurred and the mixture becomes saturated with gas. ...

   Formation of a Precipitate. ...

   Color Change. ...

   Temperature Change. ...

   Production of Light. ...

   Volume Change. ...

   Change in Smell or Taste.

7 0
3 years ago
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with incompressib
victus00 [196]

Answer:

926 N

Explanation:

Metric unit conversion:

R = 18 cm = 0.18 m

r = 5 cm = 0.05 m

The pressure exerted by the F = 12000N car on the wider arm would be ratio of the gravity over area

P = F/A = \frac{F}\pi R^2} = \frac{12000}{2*\pi*0.18^2} = 117892 Pa

The pressure must be the same on the smaller pressure for it to be able to start lifting the car. We can calculate the force f acting on it:

f = Pa = P\pi r^2 = 117892 * \pi * 0.05^2 = 926 N

5 0
3 years ago
Select the correct answer.
IgorC [24]

Answer:

D. Newton's Third Law of Motion

Explanation:

Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out

Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.

Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.

Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )

I hope this helps!

7 0
3 years ago
An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: f=-f

and we also know that the object is placed a distance of twice the focal length, so p=2f

So we can find q from the equation above

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

And the magnification of the image is given by

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

5 0
4 years ago
Read 2 more answers
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