Answer:
Explanation:
a )
Work done by force = change in kinetic energy
F x s = ( vf² - vi² ) / 2m
F = ( vf² - vi² ) / 2ms
acceleration = ( vf² - vi² ) / 2m²s
b )
F = ( vf² - vi² ) / 2ms [ calculated above ]
c )
Work done by force
= change in kinetic energy
= ( vf² - vi² ) / 2m
Answer:
The answer would be D.
Explanation:
Seven Things That Indicate a Chemical Change Is Occurring
Gas Bubbles Appear. Gas bubbles appear after a chemical reaction has occurred and the mixture becomes saturated with gas. ...
Formation of a Precipitate. ...
Color Change. ...
Temperature Change. ...
Production of Light. ...
Volume Change. ...
Change in Smell or Taste.
Answer:
926 N
Explanation:
Metric unit conversion:
R = 18 cm = 0.18 m
r = 5 cm = 0.05 m
The pressure exerted by the F = 12000N car on the wider arm would be ratio of the gravity over area
The pressure must be the same on the smaller pressure for it to be able to start lifting the car. We can calculate the force f acting on it:
Answer:
D. Newton's Third Law of Motion
Explanation:
Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out
Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.
Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.
Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )
I hope this helps!
Answer:
+1/3
Explanation:
The lens equation states that:
where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
For a diverging lens, the focal length is negative: 
and we also know that the object is placed a distance of twice the focal length, so 
So we can find q from the equation above
And the magnification of the image is given by
