Answer:
the mass of 8.03 mole of NH3 is 136.51 g
Explanation:
The computation of the mass is shown below:
As we know that
Mass = number of moles × molar mass
= 8.03 mol × 17 g/mol
= 136.51 g
Hence, the mass of 8.03 mole of NH3 is 136.51 g
We simply multiplied the number of moles with the molar mass so that the mass could come
Answer:
Temperature rises when boiling occurs.
Answer:
<u>Optical purity = 76.9231 %</u>
<u>Specific rotation of mixture = - 97.6923 °</u>
Explanation:
The mass of the racemic mixture = 3 g
It means it contains R enantiomer = 1.5 g
S enantiomer = 1.5 g
Amount of Pure R = 10 g
Total R = 11.5 g
Total volume = 500 mL + 500 mL = 1000 mL = 1 L
[R] = 11.5 g/L
[S] = 1.5 g/L
Enantiomeric excess =
=
= 76.9231 %
<u>Optical purity = 76.9231 %</u>
Also,
Optical purity = 
Optical rotation of pure enantiomer = −127 °

<u>Specific rotation of mixture = - 97.6923 °</u>
C or a one of those hope it helps !!!!