Answer:
C
Step-by-step explanation:
given a triangle with 2 sides and the angle between them given, then the area (A) is calculated as
A =
bc sinA
the 2 sides are b = 4, c = 6 and ∠ A = 35° , then
A =
× 4 × 6 × sin35° = 12 × sin35° ≈ 6.9 m² ( to the nearest tenth )
The equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
<h3>What is linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have two equation of the line:
y = -x -3 and
5y + 5x = -15
From the equation 5y + 5x = -15:
Divide by 5 on the above equation:
y + x = -3
or
y = -x -3
The two equations y = -x -3 represents the same line.
Thus, the equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
Learn more about the linear equation here:
brainly.com/question/11897796
#SPJ1
The answer o this question would be:
<span>A.The vertical line test may be used to determine whether a function is one-to-one
</span><span>D. The horizontal line test may be used to determine whether a function is one-to-one.
Vertical and horizontal line test can be used to find out whether the function, not one-to-one. The test is done by making a horizontal line (for horizontal line test) or vertical line( for vertical line test). If there are no 2 or more points of the graph that touch the line in both tests, then the function would be one-to-one</span>
Answer:
What times 7 divided by three gets you 52.5. That's what you need to ask yourself. The formula is B×H÷3.
Hope this helps
Step-by-step explanation:
Answer:
A, C, D and K
Step-by-step explanation:
Inequalities:
y ≤ −2x + 10 and y >1/2x-2
<u>Finding zeros for the first inequality:</u>
- x=0 ⇒ y= 10, point (0, 10)
- y=0 ⇒ x= 5, point (5, 0)
- Locating these 2 points and connecting to get the first line.
Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.
<u>Finding zeros for the second inequality:</u>
- x=0 ⇒ y= -2, point (0, -2)
- y= 0 ⇒ x= 4, point (4, 0)
- Locating these points and connecting to get the second line.
Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.
Now we have the space of intersection of the above inequalities.
So the points in same section are the solution.
They are:
See attached for explanation