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sukhopar [10]
3 years ago
10

A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the

Chemistry
1 answer:
wariber [46]3 years ago
3 0

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

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From the stoichiometry of the combustion reaction, we can see that 7.4 L of oxygen is consumed.

<h3>What is combustion?</h3>

Combustion is a reaction in which a substance is burnt in oxygen. The equation of the reaction is; C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l)

We can obtain the number of moles of CO2 from;

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0.33 moles of oxygen occupies 0.33 moles *  22.4 L/ 1 mole

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Which statement describes how the binary ionic compound cacl2 is named?
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I really need an answer by tonight!
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Energy is what moves forward and through a wave.

The cyclical process of the changing state and movement of water around the Earth through evaporation, condensation, and precipitation is called water cycle.

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Therefore, the water cycle helps to circulate and replenish water on earth.

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A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original am
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The half-life of the substance is 3.106 years.

<h3>What is the formula for exponential decay?</h3>
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Here,

a = the initial amount of substance

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x = time span

The equation is given in its correct form as follows:

a = a_{0}×(0.8)^{t}

As this is an exponential decay of a first order reaction, t is an exponent of 0.8.

Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:

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<h3>Substituting this into the equation:</h3>

0.5a_{0} = a_{0}×(0.8)^{t}

0.5 = (0.8)^{t}

taking log on both sides

t log 0.8 = log 0.5

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