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sukhopar [10]
3 years ago
10

A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the

Chemistry
1 answer:
wariber [46]3 years ago
3 0

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

You might be interested in
The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 Right a
yuradex [85]

The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.

<h3>How we calculate moles?</h3>

Moles of any substance will be calculated as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

2NI₃ → N₂ + 3I₂

Moles of 3.58g of NI₃ will be calculated as:

n = 3.58g / 394. 71 g/mol = 0.009 moles

From the stoichiometry of the solution, it is clear that:

2 moles of NI₃ = produce 3 moles of I₂

0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂

Hence, option (3) is correct i.e. 0.0136 moles.

To know more about moles, visit the below link:

brainly.com/question/15303663

8 0
2 years ago
The vapor pressure of liquid chloroform, CHCl3, is 100. mm Hg at 283 K. A 0.380 g sample of liquid CHCl3 is placed in a closed,
Katyanochek1 [597]

Answer:

a

No

b

100 mm Hg

Explanation:

From the question we are told that

The vapor pressure of CHCl3, is P = 100 \  mmHg =  \frac{100}{760}=  0.13156 \ atm

The temperature of CHCl3 is T  =  283 \  K

The volume of the container is V_c =  380mL =  380 *10^{-3}\  L

The temperature of the container is T_c  =  283 \  K

The mass of CHCl3 is m = 0.380 g

Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

n  =  \frac{m }{M }

Here M is the molar mass of CHCl3 with the value M  =  119.38 \ g/mol

=> n  =  \frac{ 0.380 }{119.38 }

=> n  =  0.00318 \  mols

Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

n_g  =  \frac{PV}{RT}

Here R is the gas constant with value R =  0.08206 L \  atm /mol\cdot  K

So

          n_g  =  \frac{0.13156* 380 *10^{-3} }{0.08206 * 283}

          n_g  =  0.00215 \  mols

Given that the number of moles of  CHCl3 evaporated is less than the number of moles of CHCl3  initially present , then it mean s that not all the liquid evaporated

At equilibrium the temperature of CHCl3 will be equal to the pressure of  air so the pressure at equilibrium is  100 mmHg

4 0
3 years ago
How many moles of KBr will be produced from 10.51 moles of BaBr2?
gregori [183]

Answer:

21.02moles of KBr

Explanation:

Parameters given:

Number of moles BaBr₂ = 10.51moles

Complete reaction equation:

           BaBr₂ + K₂SO₄ → KBr + BaSO₄

Upon inspecting the given equation, we find out that the atoms are not balanced on both sides of the equation:

        The balanced equation is:

           BaBr₂ + K₂SO₄ → 2KBr + BaSO₄

From the equation:

     1 mole of BaBr₂ produces 2 moles of KBr

∴   10.51 moles of BaBr₂ will yield (2 x 10.51) moles = 21.02moles of KBr

7 0
3 years ago
An unknown metal absorbs 61 J of heat, and its temperature increases by 29∘C. What is the heat capacity of the metal?
aniked [119]

Answer:

2.103 J/C

Explanation:

Quantity of heat = Heat Capacity * Temperature change

Heat Capacity = Quantity of heat / Temperature Change

Heat Capacity = 61/29

Heat Capacity = 2.103 J/C

3 0
3 years ago
A learner was assigning oxidation numbers for different elements in the compounds OF2 and NaF. The learner assigned F an oxidati
77julia77 [94]

Answer: B. No, fluorine is always assigned an oxidation number of -1.

Explanation:

6 0
2 years ago
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