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3 years ago

A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the

Chemistry

1 answer:

wariber [46]3 years ago

3 0

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

Mass of NaCl: 0.050 g

Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

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Nicotine, a component of tobacco, is composed of C, H, and N. A 5.250-mg sample of nicotine was combusted, producing 14.242 mg o

aev [14]

n - number of mole

M(CO2) = 12.0 +16.0*2 = 44.0 mg/mmol

M(H2O) = 2*1.0 +16.0= 18.0 mg/mmol

1) 14.242 mg of CO2*1 mmol/44.0g =0.32368 mmol CO2

0.32368 mmol CO2 has 0.32368 mmol C

2) 0.32368 mmol C*12 mg/1 mmol= 3.88418 mg C

3) 4.083 mg of H2O * 1 mmol/18 mg = 0.226833 mmol H2O

0.226833 mmol H2O has 2*0.226833 mmol H = 0.453666 mmol H

4) 0.453666 mmol H*1 mg/1mmol = 0.453666 mg H

5) Mass of N = 5.250 mg - 3.88418 mg (C) - 0.453666 mg (H)≈ 0.912 mg N

0.912 mg N * 1 mmol/14.0 mg = 0.0652 mmol N

6) n(C) : n(H) : n(N) = 0.32368 mmol C : 0.453666 mmol H : 0.0652 mmol N

0.0652 mmol N is a smallest value.

n(C) : n(H) : n(N) = (0.32368 mmol/0.0652 mmol) C : (0.453666 mmol H/0.0652 mmol) : (0.0652mmol/0.0652 mmol)N = 5 : 7 : 1

n(C) : n(H) : n(N) = 5 : 7 : 1

Empirical formula : C5H7N.

8 0

3 years ago

The empirical formula of a compound of iron (Mg) and sulfur (S) was determined using the following data. A sample of Mg was weig

Fudgin [204]

Answer:

The empirical formula is MgS

The number of moles Mg is 0.25 moles

There will react 0.25 moles

Option A is correct

Explanation:

Step 1: data given

The molecular weight of Mg = 24.305 g/mol

The molecular weight of S is 32.065 g/mol

mass of crucible and cover = 27.631 grams

mass of crucible, cover and Mg = 33.709 grams

mass of crucible, cover, and the compound formed 41.725 grams

Step 2: Calculate mass of Mg

Mass of Mg = mass of crucible, cover and Mg - mass of crucible and cover

Mass of Mg = 33.709 grams - 27.631 grams

Mass of Mg = 6.078 grams

Step 3: Calculate moles Mg

Moles Mg = mass Mg / atomic mass Mg

Moles Mg = 6.078 grams 24.305 g/mol

Moles Mg = 0.250 moles

Step 4: Calculate mass compound

Mass compound = mass of crucible, cover, and the compound formed - mass of crucible and cover

Mass compound = 41.725 grams - 27.631 grams

Mass compound = 14.094 grams

Step 5: Calculate mass sulfur

Mass sulfur = 14.094 grams - 6.078 grams

Mass sulfur = 8.016 grams

Step 6: Calculate moles Sulfur

Moles sulfur = 8.016 grams / 32.065 g/mol

Moles sulfur = 0.250 moles

Step 7: Calculate the mol ratio

We diviide by the smallest amount of moles

Mg: 0.250 moles / 0.250 moles = 1

S: 0.250 moles / 0.250 moles = 1

The empirical formula is MgS

The number of moles Mg is 0.25 moles

There will react 0.25 moles

Option A is correct

4 0

3 years ago

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Which of the following is NOT a way that biodiversity is important to an ecosystem?

Vitek1552 [10]

Answer:

A. Biodiversity can increase the rate of extinction

Explanation:

That statement is false because variety is better for a better ecosystem. With variety more can survive in certain situations that others cant.

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3 years ago

Which family (metals, nonmetals, or inert gases) generally has the valence electrons which are the easiest to remove from the at

zubka84 [21]

<span>Which family (metals, nonmetals, or inert gases) generally has the valence electrons which are the easiest to remove from the atom?
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The Correct Answer Is: Metals

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Brainliest?

-Nullgaming650

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3 years ago

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A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate miner

bezimeni [28]

Ferromagnesian silicate minerals (i looked it up)

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3 years ago