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Fittoniya [83]
3 years ago
7

How many moles of Oxygen (O) are in 20.15x10^25 atoms of O?

Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0

Answer: 334.6 moles of O, 167.3 moles as O2

Explanation:

20.15x10^25/6.02214076x10^23 = 334.6 as atoms, 167.3 as O2

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Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm <br> This is a Boyle’s law gas problem
morpeh [17]
P1/V1=P2/V2
1/22.4=4/x
X=4 multiple by 22.4
V2=89.6L
3 0
3 years ago
g Sucrose (C12H22O11), a nonionic solute, dissolves in water (normal freezing/melting point 0.0°C) to form a solution. If some u
DIA [1.3K]

Answer:

15.4 g of sucrose

Explanation:

Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m

0.56°C / 1.86 m/°C = m → 0.301 mol/kg

m → molality (moles of solute in 1kg of solvent)

Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg

0.301 mol/kg .  0.150kg = 0.045 moles.

We determine the mass of sucrose, by the molar mass:

0.045 mol . 342 g/1mol = 15.4 g

4 0
3 years ago
A 225 g sample of an unknown solid is heated 67C and placed into a calorimeter containing 25.6 g of water at 15.6°c. If the fina
Stella [2.4K]

Answer:

= 1.271 J/g°C

Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

But heat = mass × specific heat capacity × temperature change

Thus;

Heat released by the solid;

= 225 g × c ×(67 -53) , where c is the specific heat capacity of the metal

= 3150 c joules

Heat absorbed by water;

= 25.6 g × 4.18 J/g°C × (53-15.6)

= 4002.0992  joules

Therefore;

3150 c joules = 4002.0992 joules

c =4002.0992/3150

 <u> = 1.271 J/g°C</u>

6 0
3 years ago
Which of the following solutions is a good buffer system?A solution that is 0.10 M HCN and 0.10 M NaClA solution that is 0.10 M
patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

  • A good buffer system contains a weak acid and its salt or a weak base and its salt.
  • In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
  • HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.
8 0
3 years ago
Use the equation n2 + 3h2=2nh3 if 8.0g N2 react, how many grams of NH3 will be produced
Eduardwww [97]

the balanced equation for the formation of ammonia is

N₂ + 3H₂ ---> 2NH₃

molar ratio of N₂ to NH₃ is 1:2

mass of N₂ reacted is 8.0 g

therefore number of N₂ moles reacted is - 8.0 g / 28 g/mol = 0.286 mol

according to the molar ratio,

1 mol of N₂ will react to give 2 mol of NH₃, assuming nitrogen is the limiting reactant

therefore 0.286 mol of N₂ should give - 2 x 0.286 mol = 0.572 mol of NH₃

therefore mass of NH₃ formed is - 0.572 mol x 17 g/mol = 9.72 g

a mass of 9.72 mol of NH₃ is formed

6 0
3 years ago
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