The apparent change is the Doppler shift
Answer:
The time is 0.563 ns.
Explanation:
Given that,
Index of refraction of glass = 1.41
Distance = 12.0 cm
Angle = 33.0°
We need to calculate the refraction angle
Using Snell's law

put the value into the formula



We need to calculate the velocity of beam in glass
Using formula of velocity

Put the value into the formula


We need to calculate the time
Using formula of distance





Hence, The time is 0.563 ns.
Answer:
Current flows across a resistor.
Explanation:
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The definition of density is
Density = (mass) / (volume)
Multiply each side by 'volume' : (density) x (volume) = (mass)
Divide each side by 'density' : Volume = (mass) / (density)
Answer:
Acceleration due to gravity will be 
Explanation:
We have given length of pendulum l = 55 cm = 0.55 m
It is given that pendulum completed 100 swings in 145 sec
So time taken by pendulum for 1 swing 
We have to find the acceleration due to gravity at that point
We know that time period of pendulum;um is given by

So 

Squaring both side


So acceleration due to gravity will be 