<span>magnitude and direction</span>
Elastic potential energy = 1/2 k * change of x^2
k- coefficient
x - change in length.
to increase energy 1.5 times you have to change x (compress) into

times (it's abot 1.22 or 22%)
Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
Answer:
Energy = 18.3 Kilowatt-hour
Explanation:
Given the following data;
Power = 1220 Watts
Time = 30 * 30 = 900 minutes to hours = 900/60 = 15 hours
To find the energy consumption;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
Making energy the subject of formula, we have;
Energy = power * time
Energy = 1220 * 15
Energy = 18300 Joules
To convert energy to Kilowatt-hour;
Energy = 18300/1000
Energy = 18.3 Kilowatt-hour