Answer: 1896.55J/kg°C
Explanation:
The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = 1320 joules
Mass of material = 5.61kg
C = ? (let unknown value be Z)
Φ = 0.124°C
Then, Q = MCΦ
1320J = 5.61kg x Z x 0.124°C
1320J = 0.696kg°C x Z
Z = (1320J / 0.696kg°C)
Z = 1896.55 J/kg°C
Thus, the specific heat of the material is 1896.55J/kg°C
In my estimation I would say C, I was leaning towards A, but I believe that would merely be "incomplete combustion." I hope this was semi-helpful!
The term that describes the amount of energy transported past a given area of the medium per unit time would be "intensity." In addition, the formula for computing intensity would be:
Intensity = Energy / (Time * Area)
It can be implied that the wave would be more intense when its energy transfer rate gets increased and vibration amplitudes also increases.
In linear motion , when a body moves with uniform velocity , in time t , its linear displacement will be ;
S = r∅ S = vt
r∅ = vt
r.∅ / t = v
As
v = rw
where ∅ = 90° is the angle between between radius vector r and angular velocity w (omega )
In case ∅ ≠ 90° , we can write v = r w sin∅
It gives us v = w× r
Answer:
Explanation:
For resistance of a wire , the formula is as follows
R = ρ L / S
where ρ is specific resistance , L is length and S is cross sectional area
Given L = 14 000 m ,
S = 4.8 x 10⁻⁴ m²
specific resistance of aluminum = 2.8 x 10⁻⁸ ohm-meter
Putting the values in the formula
R = 2.8 x 10⁻⁸ x 14 x 10³ / (4.8 x 10⁻⁴ )
R = 0.8167 ohm .
= .82 ohm .
