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PilotLPTM [1.2K]
3 years ago
12

why is the concentration of helium increased in some gas mixtures that divers breath in order to reduce the partial pressure of

oxygen?
Chemistry
1 answer:
sdas [7]3 years ago
8 0

Answer:

Because of oxygen toxicity.

Explanation:

Oxygen toxicity.

Oxygen has been known to cause central nervous system (CNS) toxicity when the pressure gets higher. This toxicity can cause convulsions, and this can cause the diver to drown.

The current standard maximum safe oxygen working pressure is 1.4 atm ppO2. This is equal to 56.5m/185′ when breathing air (21% O2 / 79% N). Below that depth the fraction of oxygen in a breathing gas must be reduced, and in order to maintain this maximum pressure of 1.4 ppO2, Helium must be added.

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A student has two objects. Object 1 has a mass of 28 g and a volume of 12 cubic
bearhunter [10]

Answer:

Object 2 with a density of 0.68

Explanation:

object 2 has a lower density than water so it will float

8 0
3 years ago
1. What did Henri Becquerel discover about<br> radiation emitted from uranium salts?
Dmitriy789 [7]

Explanation:

When Henri Becquerel investigated the newly discovered X-rays in 1896, it led to studies of how uranium salts are affected by light. By accident, he discovered that uranium salts spontaneously emit a penetrating radiation that can be registered on a photographic plate.

6 0
3 years ago
Salt water can be desalinated by distillation. How much energy is needed to convert 175 g of salt water at 28.0 °C to water vapo
Vinil7 [7]

Answer:

\Delta H=4.63x10^{5}J=463kJ

Explanation:

Hello,

In this case, we find the following states:

a. Liquid salt water at 28.0 °C.

b. Liquid salt water at 102.5 °C.

c. Vapor salt water at 102.5 °C.

The first process (1) is to heat the liquid water from 28.0 °C to 102.5 °C and the second one (2) to vaporize the liquid salt water. In such a way, each process has an amount of energy that when added, yields the total energy for the process as shown below:

\Delta H=\Delta H_1+\Delta H_2\\\Delta H=mCp\Delta T+m\Delta _VH\\\Delta H=175g*5.19\frac{J}{g*K}*(375.65K-301.15K)+175g*2.26\frac{kJ}{g} *\frac{1000J}{1kJ} \\\Delta H=4.63x10^{5}J=463kJ

Best regards.

4 0
3 years ago
Pls help me also pls have the correct answer
Ann [662]

Answer:

       

Explanation:

       

4 0
2 years ago
Read 2 more answers
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of SI2. Enter the number of bo
mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

7 0
3 years ago
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