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Vlad [161]
3 years ago
5

What constant acceleration in si units must a car have to go from zero to 60 mph in 10s. what fraction of g is this?

Physics
1 answer:
Sophie [7]3 years ago
3 0

The acceleration of the car in SI units is <u>2.68m/s².</u>

The acceleration is <u>0.27</u> times the acceleration due to gravity g.

Convert the speed in mph into m/s.

1 mile = 1609 m and 1h = 3600 s.

Therefore,

v=(\frac{60 miles}{1 h} )(\frac{1609 m}{1 mile} )(\frac{1h}{3600s)} =26.82m/s

Acceleration is the rate of change of velocity. The car starts from rest , its initial velocity u = 0 and accelerates to a velocity v of 26.82 m/s in 10 s.

Use these values in the equation and calculate the acceleration.

a=\frac{v-u}{t} \\ =\frac{(26.82 m/s)-(0m/s)}{10s} \\ =2.682 m/s^2

Thus the car accelerates at a rate of <u>2.68 m/s².</u>

The acceleration due to gravity g on Earth has a value 9.81 m/s².

Find the ratio\frac{a}{g}

\frac{a}{g} =\frac{2.682m/s^2}{9.81m/s^2} \\ =0.27&#10;a=0.27g

The car's acceleration is <u>0.27 times the value of g.</u>

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A 300 g bird is flying along at 6.0 m/s and sees a 10 g insect heading straight towards it with a speed of 30 m/s. The bird open
Gelneren [198K]

Answer:

(a): The bird speed after swallowing the insect is V= 4.83 m/s

(b): The impulse on the bird is I= 0.3 kg m/s

(c): The force between the bird and the insect is F= 20 N

Explanation:

ma= 0.3 kg

va= 6 m/s

mb= 0.01kg

vb= 30 m/s

(ma*va - mb*vb) / (ma+mb) = V

V= 4.83 m/s (a)

I= mb * vb

I= 0.3 kg m/s  (b)

F*t= I

F= I/t

F= 20 N (c)

5 0
3 years ago
A playground merry-go-round has a mass of 50 kg and a diameter of 4.0 m. There are 4 children who want to ride on it. They have
mixer [17]

Answer:

B) I1 = 1680 kg.m^2          I2 = 1120 kg.m^2

C) V = 0.84m/s      T = 29.92s

D) ω2 = 0.315 rad/s

Explanation:

The moment of inertia when they are standing on the edge:

I1 = 1/2*M*R^2 + (m1+m2+m3+m4)*R^2   where M is the mass of the merry-go-round.

I1 = 1680 kg.m^2

The moment of inertia when they are standing half way to the center:

I2 = 1/2*M*R^2 + (m1+m2+m3+m4)*(R/2)^2

I2 = 1120 kg.m^2

The tangencial velocity is given by:

V = ω1*R = 0.84m/s

Period of rotation:

T = 2π / ω1 = 29.92s

Assuming that there is no friction and their parents are not pushing anymore, we can use conservation of the angular momentum to calculate the new angular velocity:

I1*ω1 = I2*ω2    Solving for ω2:

ω2 = I1*ω1 / I2 = 0.315 rad/s

5 0
3 years ago
This woman is riding a bicycle down a hill at a constant speed and in a straight line. Which change will increase the speed of t
Marina86 [1]

Answer: Um I would say maybe b

Explanation:

4 0
3 years ago
Read 2 more answers
How are the current and resistance related when the voltage of a circuit is constant
tankabanditka [31]

The law of Ohm defines the relationship in an electrical circuit between voltage, current and resistance: I = v / r. The current is directly proportional to the voltage and the resistance is inversely proportional.

3 0
3 years ago
Read 2 more answers
10 points) A rubber ball and a lump of putty of the same mass m = 0.05 kg are thrown with the same speed v=10.0 m/s in positive
snow_lady [41]

Answer:

the ball experiences the greater momentum change

Explanation:

You have to take into account that momentum change is given by

\Delta p=mv_f-mv_b

where vf and vb are the speed of the object after and before the impact.

In the case of the ball you have

\Delta p=(0.05kg)(-10.0\frac{m}{s})-(0.05kg)(10.0\frac{m}{s})=-1kg\frac{m}{s}

where the minus of vf is included due to the motion is in an opposite direction regarding with vb

And for the lump

\Delta p=(0.05kg)(10.0\frac{m}{s})-(0.05kg)(0\frac{m}{s})=0.5kg\frac{m}{s}

Hence, the ball experiences the greater change

hope this helps!!

4 0
3 years ago
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