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Vlad [161]
3 years ago
5

What constant acceleration in si units must a car have to go from zero to 60 mph in 10s. what fraction of g is this?

Physics
1 answer:
Sophie [7]3 years ago
3 0

The acceleration of the car in SI units is <u>2.68m/s².</u>

The acceleration is <u>0.27</u> times the acceleration due to gravity g.

Convert the speed in mph into m/s.

1 mile = 1609 m and 1h = 3600 s.

Therefore,

v=(\frac{60 miles}{1 h} )(\frac{1609 m}{1 mile} )(\frac{1h}{3600s)} =26.82m/s

Acceleration is the rate of change of velocity. The car starts from rest , its initial velocity u = 0 and accelerates to a velocity v of 26.82 m/s in 10 s.

Use these values in the equation and calculate the acceleration.

a=\frac{v-u}{t} \\ =\frac{(26.82 m/s)-(0m/s)}{10s} \\ =2.682 m/s^2

Thus the car accelerates at a rate of <u>2.68 m/s².</u>

The acceleration due to gravity g on Earth has a value 9.81 m/s².

Find the ratio\frac{a}{g}

\frac{a}{g} =\frac{2.682m/s^2}{9.81m/s^2} \\ =0.27&#10;a=0.27g

The car's acceleration is <u>0.27 times the value of g.</u>

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Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Troyanec [42]

Answer:

The lowest possible frequency of sound is 971.4 Hz.

Explanation:

Given that,

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Using Pythagorean theorem

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AC=\sqrt{(2.00^2+5.50^2)}

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Using formula of path difference

\Delta x=AC-BC

Put the value into the formula

\Delta x=5.85-5.50

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Using formula of frequency

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f=\dfrac{1\times340}{0.35}

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A particle leaves the origin with a speed of 3.6 106 m/s at 34 degrees to the positive x axis. It moves in a uniform electric fi
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Answer:

E = -4556.18 N/m

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Question)

from the projectile motion the horizontal distance traveled by electron is

x = u×cosA×t

⇒t = x/(u×cos A)

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F = qE

q= charge , E= strength of electric field

By newton 2nd law of motion

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Also, y = u×sinA×t - 0.5×a×t^2

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if y = 0 then

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Also, E = 2mu^2×sinA×cosA/(x×q)

Now plugging the values we get

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E = -4556.18 N/m

4 0
3 years ago
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