The answer is Decibels. <span />
Answer:
![\vec{d}=17.7km](https://tex.z-dn.net/?f=%5Cvec%7Bd%7D%3D17.7km)
Explanation:
Displacement is a vector that defines the position of a particle. The vector extends from the initial position to the final position. Therefore, the displacement only takes into account this positions, since its trajectory is not important:
![\vec{d}=6.3km-1.8km+13.2km\\\vec{d}=17.7km](https://tex.z-dn.net/?f=%5Cvec%7Bd%7D%3D6.3km-1.8km%2B13.2km%5C%5C%5Cvec%7Bd%7D%3D17.7km)
A. ![4.64\cdot 10^{11}m](https://tex.z-dn.net/?f=4.64%5Ccdot%2010%5E%7B11%7Dm)
The orbital speed of the clumps of matter around the black hole is equal to the ratio between the circumference of the orbit and the period of revolution:
![v=\frac{2\pi r}{T}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2%5Cpi%20r%7D%7BT%7D)
where we have:
is the orbital speed
r is the orbital radius
is the orbital period
Solving for r, we find the distance of the clumps of matter from the centre of the black hole:
![r=\frac{vT}{2\pi}=\frac{(3\cdot 10^7 m/s)(97200 s)}{2\pi}=4.64\cdot 10^{11}m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7BvT%7D%7B2%5Cpi%7D%3D%5Cfrac%7B%283%5Ccdot%2010%5E7%20m%2Fs%29%2897200%20s%29%7D%7B2%5Cpi%7D%3D4.64%5Ccdot%2010%5E%7B11%7Dm)
B. ![6.26\cdot 10^{36}kg, 3.13\cdot 10^6 M_s](https://tex.z-dn.net/?f=6.26%5Ccdot%2010%5E%7B36%7Dkg%2C%203.13%5Ccdot%2010%5E6%20M_s)
The gravitational force between the black hole and the clumps of matter provides the centripetal force that keeps the matter in circular motion:
![m\frac{v^2}{r}=\frac{GMm}{r^2}](https://tex.z-dn.net/?f=m%5Cfrac%7Bv%5E2%7D%7Br%7D%3D%5Cfrac%7BGMm%7D%7Br%5E2%7D)
where
m is the mass of the clumps of matter
G is the gravitational constant
M is the mass of the black hole
Solving the formula for M, we find the mass of the black hole:
![M=\frac{v^2 r}{G}=\frac{(3\cdot 10^7 m/s)^2(4.64\cdot 10^{11} m)}{6.67\cdot 10^{-11}}=6.26\cdot 10^{36}kg](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bv%5E2%20r%7D%7BG%7D%3D%5Cfrac%7B%283%5Ccdot%2010%5E7%20m%2Fs%29%5E2%284.64%5Ccdot%2010%5E%7B11%7D%20m%29%7D%7B6.67%5Ccdot%2010%5E%7B-11%7D%7D%3D6.26%5Ccdot%2010%5E%7B36%7Dkg)
and considering the value of the solar mass
![M_s = 2\cdot 10^{30}kg](https://tex.z-dn.net/?f=M_s%20%3D%202%5Ccdot%2010%5E%7B30%7Dkg)
the mass of the black hole as a multiple of our sun's mass is
![M=\frac{6.26\cdot 10^{36} kg}{2\cdot 10^{30} kg}=3.13\cdot 10^6 M_s](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B6.26%5Ccdot%2010%5E%7B36%7D%20kg%7D%7B2%5Ccdot%2010%5E%7B30%7D%20kg%7D%3D3.13%5Ccdot%2010%5E6%20M_s)
C. ![9.28\cdot 10^9 m](https://tex.z-dn.net/?f=9.28%5Ccdot%2010%5E9%20m)
The radius of the event horizon is equal to the Schwarzschild radius of the black hole, which is given by
![R=\frac{2MG}{c^2}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B2MG%7D%7Bc%5E2%7D)
where M is the mass of the black hole and c is the speed of light.
Substituting numbers into the formula, we find
![R=\frac{6.26\cdot 10^{36} kg)(6.67\cdot 10^{-11})}{(3\cdot 10^8 m/s)^2}=9.28\cdot 10^9 m](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B6.26%5Ccdot%2010%5E%7B36%7D%20kg%29%286.67%5Ccdot%2010%5E%7B-11%7D%29%7D%7B%283%5Ccdot%2010%5E8%20m%2Fs%29%5E2%7D%3D9.28%5Ccdot%2010%5E9%20m)
Answer:
A coefficient friction is a value that shows the relationship between two objects and the normal reaction between the objects that are involved.
Explanation: