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3 years ago

What are the major species in solution when solid ammonium bromate is dissolved in water?

Chemistry

1 answer:

DaniilM [7]3 years ago

6 0

The major species in solution when solid ammonium bromate is dissolved in water is shown below

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What are 3 sentences about the history of Egypt? Thank you for taking aside time to answer this. Please answer this as quickly a

Nataly_w [17]

1) The history of egypt is still unclear; artifacts, how the pyramids were built, gods and whatnot.
2) Egypt's history being uncovered in regards to curses and amulets is still being practiced in the country and some others because of the great influence it had.
3) Egyptians being able to construct such grand structures that still stand (pyramids) serves as evidence that proves Egypt was a very advanced civilization at the peak of their advancement.

5 0

2 years ago

6.10 g of a solid chemical reacts with a 10 g of a liquid chemical, the

Luda [366]

Answer: True

Explanation:

Q. 10g of white powder reacts with 10g of clear liquid. The reaction bubbles and changes color producing a black liquid that has a mass of 13g. What can be ...

4 0

3 years ago

his is the chemical formula for epinephrine (the main ingredient in adrenaline): C9H13O3N A biochemist has determined by measure

Len [333]

Answer:

3.67 moles of N

Explanation:

The epinephrine's chemical formula is: C₉H₁₃O₃N

We were told that a chemist found that in a mesaure of epinephrine, he found 33 moles of C

We must know that 9 moles of C are in 1 mol of C₉H₁₃O₃N so, let's make a rule of three:

If 9 moles of C are found in 1 mol of C₉H₁₃O₃N

Therefore 33 moles of C must be found in (33 .1) / 9 = 3.67 moles of C₉H₁₃O₃N

There is a second rule of three, then.

In 1 mol of C₉H₁₃O₃N we have 1 mol of N

Then, 3.67 moles C₉H₁₃O₃N must have (3.67 . 1) / 1 = 3.67 moles of N

Remember 1 mol of C₉H₁₃O₃N has 9 moles of C, 13 moles of H, 3 moles of O and 1 mol of N

5 0

3 years ago

Write a balanced chemical equation for the reaction that occurs when copper (II) hydroxide decomposes into copper (II) oxide and

olchik [2.2K]

Cu(OH)2 ------> CuO + H2O

8 0

3 years ago

Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3

Kryger [21]

Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

5 0

3 years ago