The correct answer is C.
Most of the time, double replacements produce one product that is soluble and one that is insoluble
This results in a precipitate within a liquid or aqueous solution
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Answer:
- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)
Explanation:
Hello,
In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:

It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:

It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.
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The answer will be bar graph
<span>Because mona means 1 atom, and a compound is made up of 2 or more atoms.</span>