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2 years ago

Arrange these molecules in order of decreasing mass: C6H14 , NO2 , Fe2O3 , and CaCO

Chemistry

1 answer:

Gennadij [26K]2 years ago

4 0

The decreasing order of the mass of the molecules are:

Fe2O3>C6H14>CaCO>NO2

Explanation:

Let us calculate the atomic mass of the molecules given:

C6H14 Atomic mass of 1 carbon atom =12.01 amu

so, 6*12+1*14 Atomic mass of hydrogen=1.007

= 86 g/mol

Atomic mass of NO2

= 14+ (2*15.9)

= 14+ 31.8

= 45.8 g/mol

Atomic mass of Fe203

( 2*55.845)+ (3*15.9)

= 159.69 g/mol

Atomic mass of CaCO

40.07+12.0107+15.99

= 68.07g/mol

The decreasing order of the mass of the molecules are:

Fe2O3>C6H14>CaCO>NO2

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3 years ago

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2 years ago

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Consider the second-order reaction:

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Initial concentration of HI is 5 mol/L.

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Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

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$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

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3 years ago

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2 years ago

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A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti

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Explanation:

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To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

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$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_3H_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

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2 years ago

Arrange these molecules in order of decreasing mass: C​6​H​14​ , NO​2​ , Fe​2​O​3 ​, and CaCO​

Arrange these molecules in order of decreasing mass: C6H14 , NO2 , Fe2O3 , and CaCO