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Roman55 [17]
3 years ago
12

a 2500 kg car going 35 m/a hits a 4000kg truck that is sitting still. What is the velocity of the truck if the car transfers all

of its momentum to the truck?
Physics
1 answer:
lianna [129]3 years ago
7 0

Answer:

Velocity of truck is 21.875 m/s.

Explanation:

Given:

Mass of the car (m) = 2500 kg

Initial speed of the car (u) = 35 m/s

Mass of the truck (M) = 4000 kg

Initial speed of the truck (U) = 0 m/s (Rest)

As per question, the total momentum of the car gets transferred to the truck.

Therefore, the final momentum of the car is 0.

Momentum is given as the product of mass and velocity.

So, if momentum becomes zero means the velocity becomes 0.

Therefore, final velocity of the car (v) = 0 m/s

Let the final velocity of truck be 'V' m/s.

Now, during collision, the total momentum remains conserved.

Initial momentum  = Final momentum.

Initial momentum of car + Initial momentum of truck = Final momentum of car + Final momentum of truck.

⇒ mu+MU=mv+MV\\\\2500\times 35+4000\times 0=2500\times 0+4000\times V\\\\87500+0=0+4000V\\\\4000V=87500\\\\V=\frac{87500}{4000}\\\\V=21.875\ m/s

Therefore, the velocity of the truck is 21.875 m/s.

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What acceleration will you give to a 24.5 kg
Ludmilka [50]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                   \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                             F = Force = 78,3 N

                                            m = Mass = 24,5 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\boxed{a=78,3\ N / 24,5\ kg}

⇒ Resolving

\boxed{a=3.19\ m/s^{2}}

Result:

The aceleration is <u>3,19 meters per second squared (m/s²)</u>

Good Luck!!

4 0
3 years ago
What is the difference between celestial and terrestrial in planetary terms? Someone please answer
andriy [413]

"Celestial"  =  anything to do with the sky

("Cielo" ..... Spanish for "sky"
 "Ceiling" ... that thing up over your head
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"Terrestrial"  =  anything to do with the Earth

("Terra" ... Latin for "Earth")
5 0
3 years ago
Pls help me, tomorrow is the deadline of my assignment ​
elena-14-01-66 [18.8K]

Answer:

6- B

7- I think A

8-B

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3 0
2 years ago
George is applying a downward force of 50N to and object that has a mass of 50kg. What is the normal force (FN) of the object wh
attashe74 [19]

The normal force acting on the object is 500 N in the upward direction

<u>Explanation:</u>

As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.

So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.

Normal\ force = Mass \times Acceleration\ due\ to\ gravity

Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then

Normal force = 50 × (-10) = -500 N

So, the normal force acting on the object is 500 N in the upward direction.

3 0
3 years ago
A sample of helium behaves as an ideal gas as energy is
alisha [4.7K]

Answer:

0.0321 g

Explanation:

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E_h = m_hc_h \Delta T = 20 J

where m_h is the mass of helium, which we are looking for:

m_h = \frac{20}{c_h \Delta T} = \frac{20}{5.193 * 120} \approx 0.0321 g

4 0
3 years ago
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