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kaheart [24]
3 years ago
10

The reaction h2co3 h2o<-> h3o hco3– takes place in water. what happens to the equilibrium when the pressure is increased?

(1 point)it favors formation of reactants.it favors formation of products.it does not change.it is conserved.
Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
5 0
I think the correct answer from the choices listed above is the first option. When the the pressure is increased, the equilibrium of the reaction would favor <span>formation of reactants. One indication would be the gas that is present in the product side. Increasing the pressure would allow the products to react and form the reactants. Hope this helps.</span>
Anarel [89]3 years ago
5 0

Answer: It does not change.

Explanation:

H_2CO_3(aq) +H_2O\rightarrow H_3O^+(aq)+HCO_3^-(aq)

According to Le Chatelier's principle, if an equilibrium reaction is subjected to a change, the reaction adjusts itself in a way to undo the change imposed.

The effect of pressure affects the equilibrium only when the reactants or products are in gaseous phase.

As none of the reactants or products is in gaseous state, there is no effect of pressure on equilibrium.

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8 0
3 years ago
| A solution containing 4.48 ppm KMnO4 exhibits
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Answer:

Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹

Explanation:

First convert Concentration from ppm inM or mol/l

⇒ Molar mass of KMnO₄ = 158.03 g

⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = \frac{4.48 X10^{-3} }{158.03X 1(lit)} = 2.83 x 10⁻⁵ molar

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According to Lambert Beer's law

     

                 ε = \frac{A}{C X l}

      or,      ε = \frac{0.06}{2.83 X 10^{-5}X1 cm }

      or,      ε = 2120.14 cm⁻¹M⁻¹

Where

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    A = absorbance

    C = Molar concentration of KMnO₄ solution

     l = length  

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