Ask question

Ask question

All categories

2 years ago

6

In this section of a circuit, a current of 2.5 A flows across R2. Find the current that flows across R3. Let R1= 3.0 ohm, R2= 8.

0 ohm, and R3= 4.0 ohm
A. 2.5 A
B. 10 A
C. 6.7 A
D. 5.0 A

2 answers:

kolbaska11 [484]2 years ago

5 0

D. 5.0A because this is right and will lead to the right answer okay you got this girl letssssss goooo googoggo Gogol

Alexeev081 [22]2 years ago

3 0

That would be (D) 5.0

You might be interested in

ANYONE who is good with the consequences of Population growth PLEASE help me!!

alekssr [168]

in china, there is a family limit for only having 1 child

at 10 billion people on earth, we will most likely run out of food supply

4 0

2 years ago

Read 2 more answers

An incident ray of light strikes water at an angle of 30°. The index of refraction of air is 1.0003, and the index of refraction

defon

Answer: It’s A

Explanation:

22 degrees

6 0

2 years ago

Read 2 more answers

a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum

7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 × $10^{-2}$ m

height (h) =8.8 cm = 8.8 × $10^{-2}$ m

total charge (q) =6.1× $10^{-7}$ C

To solve:

volume charge density (ρ)

We know;

<u> ρ =q ÷ v</u>

volume of cylinder = π ×r × r × h

volume of cylinder =3.14 × 2.1 × 2.1 × $10^{-4}$ × 8.8 × $10^{-2}$

volume of cylinder (v) = 122.23 × $10^{-6}$

<u> ρ =q ÷ v</u>

ρ = 6.1× $10^{-7}$ ÷ 122.23 × $10^{-6}$

<u>ρ = 0.04 × </u> $10^{-1}$ <u> C</u>

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

3 0

3 years ago

A ____________ galaxy has arms of gas and dust; where as _____________ galaxy is a category of galaxy that does not have a disti

Jet001 [13]

Answer:

spiral, an irregular

Explanation:

i took the test :)

3 0

3 years ago

Which type of wave is not a light wave

AlekseyPX

<em><u>A</u></em><em><u>. </u></em><em><u>R</u></em><em><u>E</u></em><em><u>D</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>S</u></em><em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>L</u></em><em><u>I</u></em><em><u>G</u></em><em><u>H</u></em><em><u>T</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>C</u></em><em><u>A</u></em><em><u>U</u></em><em><u>S</u></em><em><u>E</u></em><em><u> </u></em><em><u>THE</u></em>RE<em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>RED</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>.</u></em>

<em><u>A</u></em><em><u>L</u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u> </u></em><em><u>D</u></em><em><u>O</u></em><em><u>N</u></em><em><u>T</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>C</u></em><em><u>H</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>F</u></em><em><u>R</u></em><em><u>O</u></em><em><u>M</u></em><em><u> </u></em><em><u>G</u></em><em><u>O</u></em><em><u>O</u></em><em><u>G</u></em><em><u>L</u></em><em><u>E</u></em>

4 0

3 years ago