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Vsevolod [243]
4 years ago
8

It is possible to make a buffer that functions well near pH 7 using citric acid, which contains only carboxylate groups. Explain

. Drag the terms on the left to the appropriate blanks on the right to complete the sentences.a. decreaseb. increasec. repulsionsd. associatese. attractionsf. dissociate1. Successive deprotonations______the (−) charge density on the resulting anion.2.This results in unfavorable electrostatic_____between the carboxylate anions, which reduces the likelihood that a proton would_____.3. It is more favorable for the proton to remain bound to reduce unfavorable charge_______.
Chemistry
1 answer:
natima [27]4 years ago
7 0

Complete Question

it is possible to make a buffer that functions well near pH 7 using citric acid, which contains only carboxylate groups. Explain. Drag the terms on the left to the appropriate blanks on the right to complete the sentences.

Words : decrease, increase, repulsion, associates, attractions, dissociate

1. Successive deprotonations -------------- the (−) charge density on the resulting anion.

2.This results in unfavorable electrostatic --------- between the carboxylate anions, which reduces the likelihood that a proton would ----------

3.it is more favorable for the proton to remain bound to reduce unfavorable charge----------- . .

Answer:

1

Successive deprotonations <u>increase</u> the (−) charge density on the resulting anion.

2

This results in unfavorable electrostatic <u>repulsion</u> between the carboxylate anions, which reduces the likelihood that a proton would <u>dissociate </u>

3

It is more favorable for the proton to remain bound to reduce unfavorable charge <u>repulsion</u>

Explanation:

Generally

Successive deprotonations <u>decrease</u> the (−) charge density on the resulting anion.

This because deprotonations means removal of positive charge

This results in unfavorable electrostatic <u>repulsion</u> between the carboxylate anions, which reduces the likelihood that a proton would <u>dissociate </u>

<u />

It is more favorable for the proton to remain bound to reduce unfavorable charge <u>repulsion</u>

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Where;

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According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

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T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

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