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agasfer [191]
3 years ago
13

A radioactive substance decays according to the equation y=30( .88 )^x, where y is measured in grams of the radioactive substanc

e and x is years. In how many years will there be about half of the original amount left of this radioactive substance?
Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0
The answer is: 4 idk.
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What is this problem -12=4(x-7)-8x
Fofino [41]

-12=4(x-7)-8x

One solution was found :

                  x = -4

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :


                    -12-(4*(x-7)-8*x)=0


Step by step solution :

Step  1  :

Equation at the end of step  1  :

 -12 -  (4 • (x - 7) -  8x)  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :


  4x + 16  =   4 • (x + 4)


Equation at the end of step  3  :

 4 • (x + 4)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    4   =  0

Hope this helps you, Have a nice day.

4 0
3 years ago
A
GREYUIT [131]
The answer is D. First, it is the segment addition postulate because the two segments make up the whole. Second, it's substitution because you are substituting EF + FG for FH.

Hope this helps!
8 0
3 years ago
Read 2 more answers
What is 5/8 times 24 simplest
9966 [12]
5      24
-        -
8       1

Simplify 24 and 8. (8 goes into 24 six times.)

5      6
-       -
1      1
   
   or
5   x  6  =  30


6 0
3 years ago
G) (-6t + 2z) - (7z - 7t)​
vodomira [7]

Answer:

-13t - 5z

Step-by-step explanation:

-6t + 2z - 7z - 7t

= -13t - 5z

3 0
3 years ago
Two dice are rolled, and the sum of the face values is six. What is the probability that at least one of the dice came up a thre
gizmo_the_mogwai [7]

Answer : P(\text{ atleast one of the dice come up 3})= \frac{1}{5}

Explanation :

We know that ,

Sample space of " sum of faces is 6"= \{(3,3),(4,2),(2,4),(5,1),(1,5)\}

Atleast one of the dice come up 3 = \{(3,3)\}

So,

Probability = \frac{\text{No. of favourable outcomes}}{\text{Total no. of outcomes}}

P(\text{ atleast one of the dice come up 3})= \frac{1}{5}

8 0
3 years ago
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