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Olenka [21]
3 years ago
12

A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph

ere is then grounded. Then the ground wire is removed. A is the inner surface and B is the outer surface.
Which statement is correct?

A. The charge is –q/2 on both A and on B.
B. The charge on A is –q; there is no charge on B.
C. There is no charge on either A or B
D. The charge on A is –q; that on B is +q.
E. The charge on B is –q; that on A is +q.
Physics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

B.The charge on A is -q; there is no charge on B.

Explanation:

We are given that

Charge=+q

We have to find the correct statement.

When positive charge is placed at center of uncharged metal sphere

insulated from the ground then negative charge(-q) induced on inner

surface  A  of sphere  and the outer  surface B  is grounded then the surface is neutral .

It means there is no charge on surface B.

Hence, option B is true .

B.The charge on A is -q; there is no charge on B.

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Answer:

66.375 x 10⁻⁶ C/m

Explanation:

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∅ = Q / ε₀        -----------------(i)

Where;

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ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²

Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;

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Q = 66.375 x 10⁻⁷ C

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Where;

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Substitute these values into equation (ii) as follows;

L = 66.375 x 10⁻⁷C / 0.1m

L = 66.375 x 10⁻⁶ C/m

Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.

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Answer:

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