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egoroff_w [7]
3 years ago
15

the other end of the pipe. With the aide of the pipe, does the applied force produce a smaller torque, a greater torque, or the

same torque on the nut?
Physics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

With the addition of the pipe we have a greater torque.

Explanation:

We need to complete the description of the problem, searchin in internet we have:

"Sometimes, even with a wrench, one cannot loosen a nut that is frozen tightly to a bolt. It is often possible to loosen the nut by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe. With the aid of the pipe, does the applied force produce a smaller torque, a greater torque, or the same torque on the nut?"

With the addition of the pipe we have a greater torque, as it increases the distance or radius of torque.

We know that torque is defined, as the product of force by distance, in this way we have:

T = F * d

where:

T = torque [N*m]

F = force [N]

d = distance [m]

We can see in the above equation, that increasing the distance increases torque proportionally.

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If you double the voltage in a circuit and reduce the resistance by a factor of four what will happen to the current? A) it will
KatRina [158]
By Ohm's Law, we can relate current, voltage and resistance. It is expressed as V=IR. That is, there is a direct relationship between voltage and resistance and voltage and current.

V = IR
V1/2V1 = I1R1 / I2R1/4
1/2 = 4I1/I2
I2 = 8I1

Therefore, <span> it will increase by a factor of 8. Hope this answers the question.</span>
5 0
3 years ago
A white car is traveling at the legal speed limit v0 along an interstate highway. A blue car traveling in the same direction at
Allisa [31]

Answer:

the distance between two cars becomes d = \frac{v_o^2}{2a_b} when blue car travels at legal speed

Explanation:

Initially the relative speed of the two cars is given as

v_r = v_b - v_w

v_r = 2v_o - v_o = v_o

now the relative acceleration of blue car with respect to white car

a_r = -a_b

now the distance between two cars till the relative speed of two cars comes to zero

v_f^2 - v_i^2 = 2 a d

0 - v_o^2 = 2(-a_b)d

d = \frac{v_o^2}{2a_b}

so the distance between two cars becomes d = \frac{v_o^2}{2a_b} when blue car travels at legal speed

4 0
3 years ago
Energy in the form of heat flows from ___ to ___ until both temperatures are the ___.
Andreyy89

Answers:

The answer are Hot, Cold, and same

4 0
3 years ago
Read 2 more answers
Does anyone know number 19 and 23?
Georgia [21]
For 19 it's (d) mass.
6 0
3 years ago
A rabbit is traveling at a steady 6 m/s and (without knowing it) passes a wolf. The wolf takes off at the instant the rabbit pas
Katena32 [7]

Answer:

It takes the wolf 3 s to move as fast as the rabbit.

The wolf is 9 m from the rabbit when it reaches a speed of 6 m/s

Explanation:

The equations for the position and velocity of objects moving in a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the object at time t

x0 = initial position of the object

t = time

v0 = initial speed

a = acceleration

v = velocity of the object at time t

For the first question, let´s use the equation of velocity of the wolf to find at which time its velocity is the same as the velocity of the rabbit ( 6 m/s):

v = v0 + a · t       (v0 = 0 because the wolf starts at rest)

6 m/s = 0 + 2.0 m/s² · t

t = 3 s

Now, with this calculated time, let´s obtain the position of the wolf:

x = x0 + v0 · t + 1/2 · a · t²      (Placing the center of the frame of reference at the point when the wolf starts running makes x0 = 0)

x = 1/2 · a · t²

x = 1/2 · 2.0 m/s² · (3 s)²

x = 9 m

Now, let´s calculate the position of the rabbit. Notice that a = 0. Then:

x = x0 + v · t      x0 = 0

x = v · t

x = 6 m/s · 3 s = 18 m

The wolf is (18 m - 9 m) 9 m from the rabbit when it reaches a speed of 6 m/s

5 0
3 years ago
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