B. carbon because it's atomic number is 6
Answer:
the mesopelagic, dysphotic, or twilight zone
Explanation:
Marine zones are the divisions of the ocean. The ocean is divided into two basic parts; the pelagic or open ocean, and the benthic or sea floor.
The pelagic zone is further divided into five broad zones according to how far down sunlight penetrates and they are:
1) the epipelagic, euphotic, or sunlit zone: the top layer of the ocean where enough sunlight penetrates for plants to carry on photosynthesis.
2) the mesopelagic, dysphotic, or twilight zone: a dim zone where some light penetrates, but not enough for plants to grow.
3) the bathypelagic, aphotic, or midnight zone: the deep ocean layer where no light penetrates.
4) the abyssal zone: the pitch-black bottom layer of the ocean; the water here is almost freezing and its pressure is immense.
5) the hadal zone: the waters found in the ocean's deepest trenches.
Answer:
Explanation:
a ) 2FeCl₃ + 3Li₂S = Fe₂S₃ ( s ) + 6 LiCl
2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )
b )
3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄
3CH₃COO + 3Na⁺ + 3NH₄⁻ + PO₄⁺³ = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄
c )
HClO₄ + KOH = kClO₄ + H₂O
H ⁺ + ClO₄⁻ + K⁺ + OH⁻ = k⁺ ClO₄⁻ + H₂O
d )
NH₄OH + HNO₃ = NH₄NO₃ + H₂O
NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ + H₂O
e )
HNO₂ + KOH = KNO₂ + H₂O
H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O
f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃
H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃
g )
c ) is strong acid and strong base
d ) is weak base and strong acid
e ) weak acid and strong base
f ) Strong acid and basic salt
Answer:
Gas liquid solid
Explanation:
gases have a weak potential since they have a weak bond between molecules while in solids it's the strongest making them vibrate in a fixed position
Answer:
A = 0.023 m
Explanation:
The relation between the frequency of a radiation and its wavelength is given by the following expression.
where,
c is the speed of light (it has a constant value of 3.00 x 108 m/s)
A is the wavelength of the radiation v is the frequency of the radiation
In this case, the frequency is 13 GHz = 13 x
10° Hz = 13 x 1o° s-
The wavelength associated with this frequency is:
A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023
