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Dimas [21]
3 years ago
11

When we place a voltage of 4V across an unknown substance, 0.1A of current is seen to flow. If the material is Ohmic, how much v

oltage will be needed to dissipate a power of 10 W? (Write your answer in units of volts).
Physics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

Voltage will be 100 volt

Explanation:

We have given current through the circuit i = 0.1 A

Power dissipated P = 10 W

We know that power dissipated through any resistive cirvuit is given by

P=i^2R, here i is current and R is resistance

So 10=0.1^2\times R

R =1000 ohm

Now according to ohm's law V = iR

So Voltage V = 0.1×1000 = 100 volt  

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A child on a high dive has a mass of 40 kilograms. If the high dive is 10 meters in the air, what is the potential energy? GPE=m
saw5 [17]

Answer:

Ep = 3924 [J]

Explanation:

To calculate this value we must use the definition of potential energy which tells us that it is the product of mass by the acceleration of gravity by height.

E_{p}=m*g*h\\

where:

Ep = potential energy [J] (units of Joules)

m = mass = 40 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 10 [m]

E_{p} =40*9.81*10\\E_{p} = 3924 [J]

7 0
3 years ago
At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
(P.E) Physical Activity and Fitness.......,,,
Greeley [361]
Unscrambling

1. resting heart rate

2. overload

3. workout

4. specificity

5. cool-down

6. progression

7. warm-up

8. the last one can only be instance, but there was a typo on the paper.
4 0
3 years ago
A college student is working on her physics homework in her dorm room. Her room contains a total of 6.0 x 10^26 gas molecules. A
IceJOKER [234]

Answer:

Temperature, T = 3.62 kelvin

Explanation:

It is given that,

Total number of gas molecules, N=6\times 10^{26}

Her body is converting chemical energy into thermal energy at a rate of 125 W, P = 125 W

Time taken, t = 6 min = 360 s

Energy of a gas molecules is given by :

\Delta E =\dfrac{3}{2}NkT

T=\dfrac{2E}{3Nk}, k is Boltzmann constant

T=\dfrac{2\times P\times t}{3Nk}

T=\dfrac{2\times 125\times 360}{3\times 6\times 10^{26}\times 1.38\times 10^{-23}}

T = 3.62 K

So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.

4 0
3 years ago
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