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GrogVix [38]
3 years ago
9

Go to the roller coaster simulation and click on the “launch” button. Pay attention to the pie chart as the roller coaster moves

and fill in the blank. Be sure to keep this website open because there will be several questions related to it. The kinetic energy as the roller coaster goes downhill.
Physics
2 answers:
brilliants [131]3 years ago
4 0

Answer:

increases

Explanation:

tekilochka [14]3 years ago
3 0

Answer:

increases

Explanation:

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Which statement about thermal energy is true?
NNADVOKAT [17]

Answer:Thermal energy is a measure of a substance 's specific heat

Explanation:

7 0
3 years ago
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A sound wave has a frequency of 192Hz and travels the length of a football field, 91.4m in 0.267s.  What is the period?
Vinvika [58]

Answer:1/192 seconds

Explanation:

Period=1÷frequency

Period=1÷192

Period=1/192 seconds

6 0
3 years ago
What are the 4 energy transformations of a dash toy
Hunter-Best [27]

Answer:

Thermal/Heat energy, kinetic energy, light energy, & Electromagnetic  energy

3 0
3 years ago
2. As a pendulum swings, its energy is constantly converted between kinetic
Alex

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

6 0
3 years ago
A horizontal 745 N merry-go-round of radius
Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is  544J

Explanation:

Given :

Weight w = 745 N

Radius r =  1.45 m

Force =  56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62  = ?

Solution:

Step 1:  Finding the Mass of merry-go-round

m = \frac{ weight}{g}

m = \frac{745}{9.81 }

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I =0.5 \times m \times r^2

Substituting the values

Moment of Inertia of solid cylinder I  

=>0.5 \times 76.02 \times (1.45)^2

=> 0.5 \times 76.02\times 2.1025

=> 79.91 kg.m^2

Step 3: Finding the Torque applied T

Torque applied T = F \times r

Substituting the values

T = 56.3  \times 1.45

T = 81.635 N.m

 Step 4: Finding the Angular acceleration

Angular acceleration ,\alpha  = \frac{Torque}{Inertia}

Substituting the values,

\alpha  = \frac{81.635}{79.91}

\alpha = 1.021 rad/s^2

 Step 4: Finding the Final angular velocity

Final angular velocity ,\omega = \alpha \times  t

Substituting the values,

\omega = 1.021 \times  3.62

\omega = 3.69 rad/s

Now KE (100% rotational) after 3.62s is:

KE = 0.5 \times I \times \omega^2

KE =0.5 \times 79.91 \times 3.69^2

KE = 544J

6 0
3 years ago
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