How far has a object fallen that is traveling 98 m/s In 10 seconds
1 answer:
Answer:
The distance is, y = 489.5 [m/s]
Explanation:
To solve this problem we can use the following equation of kinematics.
where:
Vf = final velocity = 98 [m/s]
Vi = initial velocity = 0
g = gravity acceleration = 9.81 [m/s^2]
y = distance [m]
(98^2) = 0 + (2*9.81*y)
Note: the positive sign of the equation means that the acceleration of gravity acts in the direction of the movement of the object.
9604 = 19.62*y
y = 489.5 [m/s]
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Answer:
B = 62.9 N
Explanation:
This is an exercise on Archimedes' principle, where the thrust force equals the weight of the liquid
B = ρ g V
write the equilibrium equation
T + B -W = 0
B = W- T (1)
use the density to write the weight
ρ = m / V
m = ρ V
W = ρ g V
substitute in 1
B = m g -T
B = g V - T
To finish the calculation, the density of the material must be known, suppose it is steel \rho_{body} = 7850 kg / m³
calculate
B = 7850 9.8 1.20 10⁻³ - 29.4
B = 92.3 - 29.4
B = 62.9 N