1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
3241004551 [841]
2 years ago
10

The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s

ample of this radioactive substance has an initial mass of 2.5kg. Find the mass of the sample after five days.
Physics
1 answer:
Bumek [7]2 years ago
6 0

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: m_{(t)} =m_{0} e^{-kt}, where m_{0} is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

m_{(1)} =m_{0} e^{-k(1)}, but m_{(1)}=\frac{99m_{0} }{100}, so we have \frac{99m_{0} }{100}=m_{0}e^{-k}, then k=-ln(\frac{99}{100})=0.01

Now using k found we must to find m_{(5)}.

m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg

You might be interested in
For a given Prandtl-Meyer expansion, the upstream Mach number is 3 and the pressure ratio across the wave is P2/P1 = 0.4. Calcul
loris [4]

Answer:

The angle for the forward Mach line is 19.47°

The angle for the rearward Mach line is 5.21°

Explanation:

From table A-1 (Modern Compressible Flow: with historical perspective):

\frac{P_{o} }{P_{1} } =36.73 (M₁ = 3)

If Po₁ = Po₂

\frac{P_{o2} }{P_{2} } =\frac{P_{o1} }{P_{1} } *\frac{P_{1} }{P_{2} } =36.73*\frac{1}{4} =91.825

Table A-1:

\frac{P_{o2} }{P_{2} } =91.825,M_{2} =3.63

Table A-5:

v₁ = 49.76°

μ₁ = 19.47°

v₂ = 60.55°

μ₂ = 16°

θ = 60.55 - 49.76 = 10.79°

The angle for the forward Mach line is:

μ₁ = 19.47°

The angle for the rearward Mach line is:

θr = μ₂ - θ = 16 - 10.79 = 5.21°

3 0
3 years ago
How much energy in Joules (J) would an electric heater that draws 9.5 A when connected to a 120 V supply use if the heater were
leonid [27]
<h2>Energy used by heater is 8.21 x 10⁶ J</h2>

Explanation:

Energy = Power x Time

Power = Voltage x Current

Voltage = 120 V

Current = 9.5 A

Power = Voltage x Current

Power = 120 x 9.5 = 1140 W

Time = 2 hours = 2 x 60 x 60 = 7200 s

Energy = Power x Time

Energy = 1140 x 7200

Energy = 8208000 J

Energy used by heater is 8.21 x 10⁶ J

7 0
3 years ago
Which of the following elements has the lowest electronegativity?
wlad13 [49]

Answer:I believe it is D I might be wrong

Explanation:

4 0
3 years ago
Which element has the fewest valence electrons?
xxTIMURxx [149]

Answer

the answer is c because i did that before

Explanation:

8 0
3 years ago
The organelle responsible for breaking down food into energy is the
kompoz [17]
C.) Mitochondria is the answer...
7 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement does not correctly describe a theory?
    5·2 answers
  • What theory held that the earth was the center of the universe and that the sun, moon, and planets revolved around it?
    12·1 answer
  • Determine the voltage ratings of the high-and-low voltage windings for this connection and the MVA rating of the autotransformer
    15·1 answer
  • 20 Point Offer for Full Answer.
    15·1 answer
  • What would happen when there is a collision between two objects having unequal masses
    10·1 answer
  • A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun
    15·1 answer
  • A 5-mm-thick stainless steel strip (k = 21 W/m·K, rho = 8000 kg/m3, and cp = 570 J/kg·K) is being heat treated as it moves throu
    13·2 answers
  • When is something weightless
    15·1 answer
  • Pls help i dont know this
    13·1 answer
  • the diagram below shows the situation described in the problem. the focal length of the lens is labeled f; the scale on the opti
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!