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lianna [129]
3 years ago
6

Undigested and unabsored materials from the small intestine pass into the

Chemistry
1 answer:
Georgia [21]3 years ago
7 0

Answer: The unabsorbed and undigested food then passes from the ileum into the cecum, the beginning of the large intestine. This food residue is full of bacteria.

Explanation:

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A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th
Ierofanga [76]

Answer:

H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is H_{3}C--H_{3}C--CH_{3}--Br--CH_{3}. A pictorial diagram of the alkyl bromide compound is also attached.

8 0
3 years ago
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What is true about models in science?
Firlakuza [10]

Answer:

hi

Explanation:

3 0
4 years ago
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A galvanic cell at a temperature of 42°C is powered by the following redox reaction:
WARRIOR [948]

Answer:

1.99V

Explanation:

Balanced redox reaction equation:

3CU2+(aq) + 2Al(s) ------> 3Cu(s) + 2Al3+(aq)

E°cell= E°cathode- E°anode

E°cell= 0.34-(-1.66)

E°cell= 2.0V

From Nernst equation:

E= E°cell - 0.0592/n logQ

E= 2.0 - 0.0592/6 log [3.43]/[1.63]

E= 2.0- 0.0032

E= 1.99V

4 0
3 years ago
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In the image below, what is the name of the unstable molecule formed during the collision of A2 and B2?
miskamm [114]

Answer:

ig activated complex coz reactants were diaatomic molecules and they were stable initially later on we collided them so they broke into activated complex and they were highly unstable so that they bonded again with another ion!!!! so according to me B is correct OPTION!!

7 0
3 years ago
At 517 mm Hg and 24 °C, a sample of gas occuples a volume of 95 ml. The gas is transferred to a 225-ml flask and the temperature
vodomira [7]

Answer:

P_2=194.78mmHg

Explanation:

Hello,

In this case, we employ the combined ideal gas law in order to understand the volume-gas-pressure behavior as shown below:

\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}

Hence, solving for the final pressure P2, we obtain (do not forget temperature must be absolute):

P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{517mmHg*95mL*(-8.0+273.15)K}{(24+273.15)K*225mL}\\ \\P_2=194.78mmHg

Best regards.

7 0
4 years ago
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