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kicyunya [14]
3 years ago
14

A star that is moving toward an observer has its visible light shifted toward which end of the spectrum? A. blue B. red C. yello

w D. white
Physics
2 answers:
patriot [66]3 years ago
4 0

Answer:

D I took the test:

Explanation:

xxTIMURxx [149]3 years ago
3 0
La D mijo es blanco por que al pasar con rapides el color se torna blanco


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Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
3 years ago
Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector
Sav [38]
Good morning.

We see that \mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}

The magnitude(norm, to be precise) can be calculated the following way:

\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}


Now the calculus is trivial:

\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}
7 0
3 years ago
Name the type of simple machine: A ramp on the back of a moving van.
Mrac [35]
C) an inclined plane 
6 0
3 years ago
Read 2 more answers
Feathers and a bowling ball are dropped in a vacuum, airless environment. Which one will hit the ground first?
Reil [10]

Answer: at the same time

Explanation: in a vacuum, there isnt air, right? so there isnt gravity pushing down on the heavier object, so they will both land at the same time.

good? :)

8 0
3 years ago
A rectangular metal tank with an open top is to hold 171.5 cubic feet of liquid. what are the dimensions of the tank that requir
Semmy [17]
To minimize the material usage we have to have the volume requested with the minimum surface area.
The volume is:
171.5 =xyz
And the surface is:
S=xy+2xz+2yz
From the first equation we get:
z=\frac{171.5}{xy} ; k=171.5\\ z=\frac{k}{xy}\\
I will use k instead of a number just for the conveince.
We plug this into the second equation and we get:
S=xy+2k\frac{1}{x}+2k\frac{1}{y}
To find the minimum of this function we have to find the zeros of its first derivative.
Sx will denote the first derivative with respect to x and Sy will denote the first derivative with respect to Sy.
S_x=y-2k\frac{1}{x^2}\\ S_y=x-2k\frac{1}{y^2}
Now let both derivatives go to zero and solve the system (this will give us the so-called critical points).
0=y-2k\frac{1}{x^2}\\
0=x-2k\frac{1}{y^2}\\
y=2k\frac{1}{x^2}\\
x=2k\frac{1}{y^2}\\
Now we plug in the first equation into the other and we get:
x=\frac{\frac{2k}{1}}{\frac{4k^2}{x^4}}\\
x^3=2k\\
x=(2\cdot171.5)^{1/3}\\
x=7

Now we can calculate y:
y=2k\frac{1}{x^2}\\
y=2\cdot 171.5\frac{1}{7^2}=7
And finaly we calculate z:
z=\frac{171.5}{xy}\\
z=\frac{171.5}{7\cdot7}=3.5
And finaly let's check our result:
V=xyz=7\cdot7\cdot3.5=171.5
4 0
3 years ago
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