Need help , worth 50 points

Mathematics

2 answers:

GarryVolchara [31]3 years ago

7 0

Answer:

To get rid of the x you will need to make the positive value of x in one equal the negative value in the other number.

multiply A by 5/2 or B by 2/5 which is either 2 or 3, but x is negative already, so you add. And the answer is C

aev [14]3 years ago

5 0

Well to eliminate x you will need to make the positive value of x in one equal the negative value in the other.
hence you can either multiply A by 5/2 or B by 2/5 which brings you to either 2 or 3, but as x is negative in B already, you add. resulting in the answer being the 3rd one down (i think)

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A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t

Iteru [2.4K]

Answer:

Step-by-step explanation:

According to the described rule, we have

$a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}$