<span>
The taut guitar string haspotencial energy which we can see in action.</span> <span>· so option a is correct.</span>
The value of x in the given right triangle in a semicircle is determined as 21.
<h3>What is the measure of a triangle in a semicircle?</h3>
The triangle in a semicircle is always a right angle triangle.
From the figure shown, we can say that the triangle G J K is right triangle and m<K = 90degrees.
Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:
4x + 6 = 90
4x = 90 - 6
4x = 84
x = 21
Thus, the value of x in the given right triangle in a semicircle is determined as 21.
Learn more about right angle here: brainly.com/question/64787
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At a particular location, when an an increase in the rate at which water moves from the hydrosphere to the atmosphere, an increase in humidity is expected at that location. The term "humidity" generally refers to the amount of water vapor in the atmosphere.
The star looks like a desirable hunk of masculinity to Jane. But to John, the star looks like a wimpy momma's boy who might compete with him for Jane's attention. Jane and John have different impressions of the star because of their gender-specific instincts that have evolved during thousands of millenia of human evolution.
Answer:
A) d = 11.8m
B) d = 4.293 m
Explanation:
A) We are told that the angle of incidence;θ_i = 70°.
Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;
tan 70° = d/4.3m
Where d is the distance from point B at which the laser beam would strike the lakebottom.
So,d = 4.3*tan70
d = 11.8m
B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)
So,
n1*sinθ_i = n2*sinθ_r
Thus; sinθ_r = (n1*sinθ_i)/n2
sinθ_r = (1 * sin70)/1.33
sinθ_r = 0.7065
θ_r = sin^(-1)0.7065
θ_r = 44.95°
Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;
d = 4.3 tan44.95
d = 4.293 m
