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True [87]
3 years ago
6

a pulley system has an efficiency of 74.2%. If you perform 200 J of work how much useful work does the pulley perform

Physics
1 answer:
oksian1 [2.3K]3 years ago
3 0

<u>Answer:</u>

148.4 J

<u>Explanation:</u>

We are given that the efficiency of a pulley system is 74.2% and we are to calculate the useful work done if we perform 200 J of work

We know that efficiency is basically the measure of how efficient a process is.

The formula of efficiency is given by:

<em>Efficiency = useful energy output / total energy input</em>

So substituting the given values in the above formula:

0.742 = Useful energy / 200 J

Useful energy = 148.4 J

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Brilliant_brown [7]

Answer:

Explanation:

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force on charged particle ( proton )

F = e ( v x B )

2.06  x10⁻¹⁶ j = 1.6 x 10⁻¹⁹ [ 1.5 x 10³ i x ( Bx i + Bz k) ]

2.06  x10⁻¹⁶ j = - 1.6 x 10⁻¹⁹ x 1.5 x 10³  Bz j) ]

2.06  x10⁻¹⁶ = - 1.6 x 10⁻¹⁹ x 1.5 x 10³  Bz

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force on charged particle ( electron )

F = e ( v x B )

8.40  x10⁻¹⁶ j = -1.6 x 10⁻¹⁹ [ - 4.4 x 10³ k  x ( Bx i + Bz k) ]

8.4  x10⁻¹⁶ j =  1.6 x 10⁻¹⁹ x 4.4 x 10³  Bx j ]

- 8.4  x10⁻¹⁶ =  1.6 x 10⁻¹⁹ x 4.4 x 10³  Bx

Bx =  - 1.19

Magnetic field = - 1.19 i - .8583 k

magnitude = √ (1.19² + .8583²)

= 1.467 T

If it is making angle θ with x - axis in x -z plane

Tanθ = (.8583 / 1.19 )

36⁰ .

C )

v = - 3.7 x 10³j m /s

e = - 1.6 x 10⁻¹⁶ C

Force = F = e ( v x B )

= -1.6 x 10⁻¹⁹ [ -3.7 x 10³ j  x ( Bx i + Bz k) ]

=  - 1.6 x 10⁻¹⁹ x 3.7 x 10³  Bx  k -1.6 x 10⁻¹⁹ x 3.7 x 10³Bzi ]

=    5.08 i - 7.04 k

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5 0
3 years ago
A disk of radius R = 7.52 cm is centered at the origin and lies along the y – z plane. The disk has a surface charge density σ =
mr Goodwill [35]

Answer:

The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C

Explanation:

The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m), will be evaluated as follows:

Since x > 0

E_{x} = 2\pi \sigma k [1-\frac{x}{\sqrt{x^2 +R^2}}]

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E_{x} = 2\pi ( 5.88X10^{-6})(8.99 X10^9)[1-\frac{1.01}{\sqrt{1.01^2 +0.0752^2}}]

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5 0
4 years ago
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Kazeer [188]

Answer:

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p= (9)/(3)

p= 3

p= 3 g/cm³

Explanation:

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