Answer:
9.38 m/s
Explanation:
Mass is conserved.
m₁ = m₂
ρ₁ Q₁ = ρ₂ Q₂
Assuming no change in density:
Q₁ = Q₂
v₁ A₁ = v₂ A₂
v₁ π r₁² = v₂ π r₂²
v₁ r₁² = v₂ r₂²
Plugging in values:
(1.50 m/s) (0.0250 m)² = v (0.0100 m)²
v = 9.38 m/s
Answer:
Im pretty sure it is 30 but if you search it up it says 16.(insert random numbers) so im not sure
Explanation:
To solve this problem it is necessary to apply the concepts related to energy as a function of voltage, load and force, and the definition of Force given by Newton in his second law.
By definition we know that force is equal to
F= ma
Where,
m = mass (at this case of an electron)
a = Acceleration
But we also know that the Energy of an electric object is given by two similar definitions.

Where,
F= Force
q = Charge of proton/electron

V = Voltage
d = Distance
Equating and rearrange for F,


The two concepts of force can be related to each other, then

Acceleration would be,

Replacing with our values we have that the acceleration is



Now through the cinematic equations of motion we know that,

Where,
Final velocity
Initial velocity
a = Acceleration
x = Displacement
Re-arrange to find v_f,



Therefore the electron's speed when it is 0.1 cm from the negative plate is
yup they r equal as mentioned above is equal magnitude and direction! so they r totally equal.
as one vector has 2 things which is used to define it ->
- Magnitude
- direction
so if both r equal then both vectors r equal vectors
Just did some researching for you and the correct answer to this question would be D, all of the above.
Hope this helps, good luck!