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Sunny_sXe [5.5K]
4 years ago
14

Friction in a car's engine produces some wasted _____ energy.

Physics
2 answers:
alexira [117]4 years ago
7 0
The answer to this is B.
Soloha48 [4]4 years ago
7 0
The answer is A because a car's engine produces heat 
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Water flows through a pipe of
snow_lady [41]

Answer:

9.38 m/s

Explanation:

Mass is conserved.

m₁ = m₂

ρ₁ Q₁ = ρ₂ Q₂

Assuming no change in density:

Q₁ = Q₂

v₁ A₁ = v₂ A₂

v₁ π r₁² = v₂ π r₂²

v₁ r₁² = v₂ r₂²

Plugging in values:

(1.50 m/s) (0.0250 m)² = v (0.0100 m)²

v = 9.38 m/s

3 0
3 years ago
PLEASE HURRY MY TIME FOR THE TEST IS RUNNING OUT !Tommy lives 10 miles from school. How many kilometers would this
bekas [8.4K]

Answer:

Im pretty sure it is 30 but if you search it up it says 16.(insert random numbers) so im not sure

Explanation:

6 0
3 years ago
Read 2 more answers
Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron ent
dmitriy555 [2]

To solve this problem it is necessary to apply the concepts related to energy as a function of voltage, load and force, and the definition of Force given by Newton in his second law.

By definition we know that force is equal to

F= ma

Where,

m = mass (at this case of an electron)

a = Acceleration

But we also know that the Energy of an electric object is given by two similar definitions.

1) E= \frac{F}{q}

Where,

F= Force

q = Charge of proton/electron

2) E = \frac{V}{d}

V = Voltage

d = Distance

Equating and rearrange for F,

\frac{F}{q} = \frac{V}{d}

F = \frac{Vq}{d}

The two concepts of force can be related to each other, then

ma = \frac{Vq}{d}

Acceleration would be,

a = \frac{Vd}{dm}

Replacing with our values we have that the acceleration is

a = \frac{Vq}{dm}

a = \frac{(170)(1.6*10^{-19})}{(2*10^{-2})(9.1*10^{-31})}

a = 1.49*10^{15}m/s^2

Now through the cinematic equations of motion we know that,

V_f^2-V_i^2 = 2ax

Where,

V_f = Final velocity

V_i = Initial velocity

a = Acceleration

x = Displacement

Re-arrange to find v_f,

v_f = \sqrt{v_i^2+2ax}

v_f = \sqrt{2.5*10^5+2*(1.49*10^{15})(0.1*10^{-2})}

v_f = 1.726*10^6 m/s

Therefore the electron's speed when it is 0.1 cm from the negative plate is 1.726*10^6 m/s

4 0
3 years ago
Help me do the c.....​
frez [133]

yup they r equal as mentioned above is equal magnitude and direction! so they r totally equal.

as one vector has 2 things which is used to define it ->

  1. Magnitude
  2. direction

so if both r equal then both vectors r equal vectors

3 0
3 years ago
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Which is a type of aerobic exercise?
stira [4]
Just did some researching for you and the correct answer to this question would be D, all of the above.
Hope this helps, good luck!
7 0
4 years ago
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