356,000 would be the answer I believe
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
Convert to a mixed number:
239/42
Divide 239 by 42:
4 | 2 | 2 | 3 | 9
42 goes into 239 at most 5 times:
| | | | 5
4 | 2 | 2 | 3 | 9
| - | 2 | 1 | 0
| | | 2 | 9
Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
| | | | 5 | (quotient)
4 | 2 | 2 | 3 | 9 |
| - | 2 | 1 | 0 |
| | | 2 | 9 | (remainder)
The quotient of 239/42 is 5 with remainder 29, so:
Answer: 5 29/42
Answer:
nice bro good for you :)
Step-by-step explanation:
Answer:

Step-by-step explanation: