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puteri [66]
3 years ago
5

Draw the partial (valence-level) orbital diagram, and write the symbol, group number, and period number of the element:

Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

a) The element is Manganese (Mn)

b) The element is Zirconium (Zr)

Explanation:

The step by step analysis and explanation is as shown in the attachment

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When a 3.80 g sample of magnesium nitride (MW 101g/mol) is reacted with 3.30 g of water, 3.60 g of MgO is formed. What is the pe
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  The  percent   yield  of  this   reaction  is  calculated  as  follows
  Mg3N2  +  3H2O  =2NH3  +  3Mgo

  calculate  the   theoretical  yield,
moles=mass/molar  mass
moles Mg3N2=  3.82  g/100g/mol=  0.0382  moles(limiting  regent)

moles of  H2o=  7.73g/18g/mol  = 0.429  moles ( in  excess_)

by  use   of  mole  ratio   between  Mg3N2  to  MgO  which  is  1:3   the    moles  of MgO =  0.0382  x3  = 0.1146  moles
mass =moles  x molar  mass

the  theoretical  mass  is therefore =  0.1146mole  x  40  g/mol  =  4.58 grams

The %  yield  =  actual  mass/theoretical  mass  x1000

=  3.60/4.584  x100=  78.5%
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Why is peer review important when publishing experimental results? A. Peer review makes the experiment repeatable. B. Peer revie
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The answer is D. At least that's what I think.
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Circle the letter of cach sentence that is true about silica.
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A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

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3 years ago
Give the electronic configuration of carbon atom.​
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Answer:

1s2 2s2 2p2

Explanation:

it has 6 electrons in two energy levels so the sub levels are 1s, 2s and 2p

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