Answer:
Explanation:
make observations, draw conclusions, develop a hypothesis, analyze data.
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
<h3>What is potential energy?</h3>
It is the energy due to the position.
A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:
U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J
A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:
U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J
The increase in the potential energy is:
518 J - 283 J = 235 J ≈ 240 J
A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).
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Answer:
a)6.34 x
W/m²
b)1.37 x
W/m²
c) see explanation.
Explanation:
a)The relation of intensity'I' of the radiation and area 'A' is given by:
I= P/A
where P= power of sunlight i.e 3.9 x
J
and the area of the sun is given by,
A= 4π
=> 4π
A=6.15 x
m²
= 3.9 x
/ 6.15 x
=><u> 6.34 x </u>
<u>W/m²</u>
b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space
A= 4π
Now R= 1.5 x
m
A= 4π x 1.5 x
=>2.83 x
m²
The power that each square meter of Earths surface receives
= 3.9 x
/2.83 x
=><u>1.37 x </u>
<u> W/m²</u>
<u />
c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.
Answer:
t = 1
Explanation:
you dont know the value of the variable
Answer
given,
distance of first satellite = 48,000 Km
distance of second satellite = 64,000 Km
orbital period = 6.39 day
Using equation of time period

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.
from the first satellite




for second satellite


