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Viefleur [7K]
2 years ago
5

A 16.0 kg crate rests on a shelf 1.80 m above the floor in a warehouse. A forklift is used to raise the crate to a shelf 3.30 m

above the warehouse floor. What is the increase in potential energy of the crate?
Group of answer choices

a. 240 J

b. 250 J

c. 230 J

d. 260 J
Physics
1 answer:
klio [65]2 years ago
5 0

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

<h3>What is potential energy?</h3>

It is the energy due to the position.

A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:

U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J

A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:

U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J

The increase in the potential energy is:

518 J - 283 J = 235 J ≈ 240 J

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

Learn more about potential energy here: brainly.com/question/23979653

#SPJ1

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an athlete runs 5.4 laps around a circular track that is 400.0 m long. If this takes 540 s, what is the average velocity of the
Slav-nsk [51]

Answer:

Average velocity is 0.296 m/s.

Average speed is 4.0  m/s.

Explanation:

Given:

Distance of the circular track is, D=400.0\ m

Number of laps ran is, n=5.4

Time taken for the run is, t=540\ s

Now, total distance covered in 5.4 laps = D_T=D\times n=400\times 5.4=2160\ m

Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.

Distance covered in 0.4 laps is, \textrm{Displacemet}=0.4\times 400=160\ m

Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.

Now, average velocity is given as:

v_{avg}=\frac{\textrm{Displacemet}}{t}=\frac{160}{540}=0.296\ m/s

Average speed is the ratio of total distance covered to total time taken.

So, average speed = \frac{D_T}{t}=\frac{2160}{540}=4\ m/s

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4 years ago
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4 0
3 years ago
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Rus_ich [418]
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3 years ago
Is sound potential or kinetic energy
qwelly [4]

Answer:

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Explanation:

Hope this helps :D

3 0
3 years ago
A runner starts from rest and in 2 s reaches a speed of 7 m/s. If we assume that the speed changed at a constant rate (constant
PtichkaEL [24]

Answer:

v=3.5\frac{m}{s}

Explanation:

The average speed is defined as:

v=\frac{\Delta x}{\Delta t}

Using the equations for uniformly accelerated motion, we calculate the runner's acceleration:

a=\frac{v_f-v_o}{2}\\a=\frac{7\frac{m}{s}-0\frac{m}{s}}{2s}\\a=3.5\frac{m}{s^2}

Now, we can calculate the distance that the runner travels:

\Delta x=v_0t+\frac{at^2}{2}\\\Delta x=(0\frac{m}{s})(2s)+\frac{3.5\frac{m}{s}(2s)^2}{2}\\\Delta x=7m

Finally, we calculate the runner's average speed:

v=\frac{7m}{2s}\\v=3.5\frac{m}{s}

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