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3 years ago

Help meeeee

2 answers:

7 0

You just have to simpy add the vectors together. Draw a picture to help you. Your verticle run is a vector that has a magntiude of 22m along the x axis with an angle of 0, and your climb has is a vector with a magnitude of 4.8 along the y axis and an angle of 90 degreed with respect to the x axis therefore add all of the x components and y components. you will find that the resultant vector has a xcomponent of 22m and a y component of 4.8m so draw a graph the point will be (22,4.8) and then you can simply measure the angle.

Umnica [9.8K]3 years ago

7 0

It's going to be the angle whose tangent is (4.8 / 22). That's about 0.2182, and you can easily use your calculator to find the angle that has that tangent.

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A child and her mother are at the park the child walked around a rectangular park while her mom waits on the bench the child ret

Genrish500 [490]

The distance is just the perimeter of the rectangle:

P = 2(411) + 2(475)
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6 0

3 years ago

onsider 1000 mL of a 1.00 × 10-4 M solution of a certain acid HA that has a Ka value equal to 1.00 × 10-4. Water was added or re

solmaris [256]

Answer:

The volume of the final solution, V = 0.0305L

Explanation:

Number of moles = Concentration * volume

Concentration of HA = 1.00 * 10⁻⁴M

Volume of HA = 1000mL = 1 L

Number of moles of HA = 1.00 * 10⁻⁴ * 1

Number of moles of HA = 1.00 * 10⁻⁴ mols

Equation of reaction:

HA → H⁺ + A⁻

If 1 mol of HA produces 1 mol of H⁺ and A⁻, 1.00 * 10⁻⁴ mol of HA will produce 1.00 * 10⁻⁴ mol of H⁺ and A⁻.

Since only 16% dissociation occurs = 0.16

Number of moles of H⁺ produced = 0.16 * 1.00 * 10⁻⁴

Number of moles of H⁺ produced = 1.6 * 10⁻⁵mols

Number of moles of A⁻ produced = 0.16 * 1.00 * 10⁻⁴

Number of moles of A⁻ produced = 1.6 * 10⁻⁵mols

Since 16% of HA dissociated into H⁺ and A⁻, 84% of HA is left

Number of mols of HA left = 0.84 * 1.00 * 10⁻⁴

Number of mols of HA left = 8.4 * 10⁻⁵mols

Concentration = num of moles/volume

Let the volume of the final solution be V

Conc of HA = 8.4 * 10⁻⁵/V

Conc of H⁺ = 1.6 * 10⁻⁵/V

Conc of A⁻ = 1.6 * 10⁻⁵/V

To calculate the dissociation constant

$k_{a} = [H^{+} ][A^{-} ]/[HA]$

$k_{a}= [1.6 * 10^{-5} /V][1.6 * 10^{-5} /V]/[8.4 * 10^{-5} /V]\\k_{a}= 3.05 * 10^{-6} /V\\k_{a} = 1.00 * 10^{-4}\\ 1.00 * 10^{-4} = 3.05 * 10^{-6} /V\\V= 3.05 * 10^{-6}/ 1.00 * 10^{-4}\\V=3.05 * 10^{-2}\\V=0.0305 L$

3 0

3 years ago

A remote-controlled plane has a mass of 0.386 kg and flies in a circle with a radius of 75 m. The centripetal force on the plane

kolezko [41]

Answer:

28 m/s

Explanation:

correct

6 0

4 years ago

Which statement MOST LIKELY describes what changes when moving downwards from fluorine to chlorine on the periodic table?

slava [35]

Answer:

B) The ionic charge of the elements changes from positive to negative

Explanation:

In the case when there is a moving towards downward direction from fluorine to chlorine on the periodic table so this represent that there are an ionic elements charge varies i.e. from positive to negative

Therefore as per the given situation the option b is correct

And, the rest of the options are wrong

3 0

3 years ago

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Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char

lorasvet [3.4K]

Answer:

$F'=2F$

Explanation:

The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

$F=\frac{kq_1q_2}{d^2}$

In this case, we have $q_1'=2q_1$ :

$F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F$

3 0

3 years ago