Some organisms that could not survive where cats, dogs, birds, horses, fish, cows, every animal that was in hurricane Katrina was affected by it. Some of these animals were able to survive and others were rescued from near death.
Most of the animals could not adapt to this change because they are not used to this type of change. The water was too strong for the fish and when the water brought the fish into any water/sea animal there was also medal because the water in through peoples houses (pretty much the man-made stuff that's not meant for sea is killing the animals in the water).
Any animal that was left behind was affected. The animals could not adapt to this change they have never experienced something that tragic before, how they survived? Well, the animals that survived was mainly because of there natural instinct, before an earthquake or anything hits there are many animals that can sense the storm coming before it even hits and in this situation, the animal could, wake up, run to owner, flee, run to higher ground, and if they cant sense it. They see whats going on around them and then they know something is wrong.
Answer:
Reaction 1 is balanced but 2 is not balanced , the balance equation are :
1. 
2.
Explanation:
Balanced Equations : These are the equation which follows the law of conservation of mass .
The total number of atoms present in reactant is equal to total number of atoms present in product.
1. 
This is acid - base type reaction where
act as Acid
act as weak base
Reactant :
,
Number of atoms of :
C = 2 (
) + 1 (
)
= 2 + 1
= 3
H = 4(
) + 1 (
)
= 4 + 1
5
O = 2(
) + 3 (
)
= 5
Na = 1 (
)
= 1
Product :
,
, 
Number of atoms :
C = 1(
) + 2(
)
= 1 + 2
= 3
H = 2(
) + 3(
)
= 2 + 3
= 5
O = 1(
) + 2(
)
+2(
= 1 + 2 + 2
= 5
Na = 1(
= 1
Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction
2.
This is double displacement reaction .
Check the balancing in both reactant and products should be :
Na = 2
H = 2
Ca = 1
C = 2
O = 6
Cl = 2
Answer is
C. 2.07 M
For explanation
M1V1 = M2V2
M2 = (M1V1)/V2
M2 = (1.5M x 345ml) / 250 ml
:. M2 = 2.07 M
The answer is homogenous i think