Answer:
I found the experience tasking
Explanation:
I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.
I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn
Answer:
284.8 kgm/s
Explanation:
Impulse: This can be defined as the product of force and time of a body. The S.I unit of impulse is N.s mathematically.
Impulse = Force × time
Change in momentum: This is the product of the mass of a body and its change in velocity. The unit of change in momentum is kgm/s.
Mathematically,
momentum = mass×change in velocity
Deduction from newton's second law of motion,
Impulse = change in momentum
Therefore,
Change in Momentum = Force×time
ΔM = F×t................. Equation 1
Where F = force = 89 N, t =time = 3.2 s.
Substitute into equation 1
ΔM = 89×3.2
ΔM = 284.8 kgm/s
Thus the change in momentum = 284.8 kgm/s
Answer:
i think the answer is "B"
Explanation:
the particles in a gas are more far apart and have more kinetic energy than liquid because they are more close together and have less kinetic energy than gas.
Answer:
(a) 2.45×10⁵ N/m
(b) 0.204 m
Explanation:
Here we have that to have a velocity of 2.25 m/s then the relationship between the elastic potential energy of the spring and the kinetic energy of the rocket must be
Elastic potential energy of the spring = Kinetic energy of the rocket
Where:
k = Force constant of the spring
x = Extension of the spring
m = Mass of the rocket
v = Velocity of the rocket
Therefore,
or
(b) Since the maximum acceleration is given as 5.00×g we have
Maximum acceleration = 5.00 × 9.81 = 49.05 m/s²
Hence the force on the rocket is then;
Force = m×a = 1020 × 49.05 = 50,031 N
Therefore,
(a) From which
or
Force constant of the spring, k = 2.45×10⁵ N/m.
