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dybincka [34]
3 years ago
8

Zoe is shown two mystery boxes that are both 8,000cm3. Her teacher tells her that one mystery box is filled with rocks and the o

ther is filled with napkins. Without touching the boxes, Zoe is asked to determine which box has the napkins.

Physics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

The box of rocks will have depression which can be seen without touching the box.

Explanation:

The density of rocks is very large as compared with napkins. So, the weight of the rocks will be much more greater than that of napkins.

As both boxes have same volume the heavier box will show depression on the lower surface as compared to the lighter box. So, the box of rocks will have depression which can be seen without touching the box.

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Electric fields are vector quantities whose magnitudes are measured in units of volts/meter (V/m). Find the resultant electric f
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Answer:

The resultant field will have a magnitude of 241.71 V/m, 30.28° to the left of E1.

Explanation:

To find the resultant electric fields, you simply need to add the vectors representing both electric field E1 and electric field E2. You can do this by using the component method, where you add the x-component and y-component of each vector:

E1 = 99 V/m, 0° from the y-axis

E1x = 0 V/m  

E1y = 99 V/m, up

E2 = 164 V/m, 48° from y-axis

E2x = 164*sin(48°) V/m, to the left

E2y = 164*cos(48°) V/m, up

Ex: E_{1_{x}} + E_{2_{x}} = 0 V/m - 164 *sin(48) V/m= -121.875 V/m\\Ey: E_{1_{y}} + E_{2_{y}} = 99 V/m + 164 *cos(48) V/m = 208.74 V/m\\

To find the magnitude of the resultant vector, we use the pythagorean theorem. To find the direction, we use trigonometry.

E_r = \sqrt{E_x^2 + E_y^2}= \sqrt{(-121.875V/m)^2 + (208.74V/m)^2} = 241.71 V/m

The direction from the y-axis will be:

\beta = arctan(\frac{-121.875 V/m}{208.74 V/m}) = 30.28° to the left of E1.

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4 years ago
If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that
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Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  P_1 =  1.50 \  atm

   The volume of the second bulb is  V_2 =  0.800 \  L

   The  final pressure of the gas is  P_2 =  671 \ torr =  \frac{671 }{ 760}  =  0.883 \ atm

Let the unknown volume be represented as V_1 =  V \   L

Generally from Boyle's law we have that

      P_1 *  V_1 =  P_2 * V_2

=>   1.50 *  V =   0.883  * 0.800

=>   V  = 0.479 \ L

         

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