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Tju [1.3M]
3 years ago
12

If you weighted 130 lbs on Earth how much would you weigh on the moon?

Physics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

21

Explanation:

Weight on the moon is 16.5 % of weight on earth

Weight on moon = 0.165 * 130

Weight on moon = 21 lbs

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Which of the following will cause an increase in gas pressure in a closed container?
Shalnov [3]
The answer is A. Or the first option. Pressure is changed by lowering the pressure, not reducing the volume. You would assume its C but its A. 
5 0
3 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
2 years ago
A constant net torque is applied to a rotating object. Which of the following best describes the object's motion? A constant net
ahrayia [7]

Answer:

The object will rotate with constant angular acceleration

Explanation:

According to the Newton's Second Law for Whenever there is more than one torque acting on a rigid body that posses fixed axis, the moment of inertia as well as the angular acceleration is equals or proportional to the summation of the torques. It gives details on the relationship between rotational kinematics and torque as well as moment of inertia. This can be represented by the below equation.

∑iτi=Iα.

.Therefore when constant net torque is applied to object that is rotating, the object will rotate with constant angular acceleration

7 0
3 years ago
local AM radio station broadcasts at a frequency of 685.9 kHz. Calculate the wavelength at which they are broadcasting. Waveleng
natta225 [31]

Answer:

λ = 437 m.

Explanation:

  • Since a radio wave is a electromagnetic type of wave, it propagates approximately at the same speed of light in vacuum, 3*10⁸ m/s.
  • As in any wave, there exist a fixed relationship between the propagation speed, the wavelength and the frequency of the radio wave, as follows:

       c = \lambda* f (1)

  • Replacing by the values of the speed and the frequency, and solving for the wavelength λ, we get:

       \lambda = \frac{c}{f} =\frac{3e8 m/s}{685.9e31/s} =437 m  (2)

8 0
2 years ago
IP The x and y components of a vector r⃗ are rx = 16 m and ry = -8.5 m , respectively
fiasKO [112]

as it is given that

r_x = 16 m

r_y = -8.5 m

now we will have

\vec r = 16 \hat i - 8.5 \hat j

now the magnitude of this vector is given as

|r| = \sqrt{16^2 + 8.5^2}

|r| = 18 m

now to find the direction we can use

tan\theta = \frac{r_y}{r_x}

tan\theta = \frac{-8.5}{16}

\theta = tan^{-1}(-0.53)

\theta = - 28^0

4 0
3 years ago
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