1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna35 [415]
3 years ago
8

What kind of intermolecular forces act between an ammonia molecule and a hydrogen peroxide?

Chemistry
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

  1. Dispersion Force
  2. Dipole- Dipole force
  3. Hydrogen bond

Explanation:

<u>Dispersion Force</u> :

These are the types of intermolecular forces that generally exists in all atoms and molecules and are results of unsymmetrical charged clouds.

<u>Dipole-Dipole Force: </u>

These are the intermolecular forces that are present between atoms of different electronegativities.

<u>Hydrogen Bond:</u>

These are the forces that are present when hydrogen atom is covalently bonded to an atom which is high in electronegativity.

You might be interested in
Which is/are part of the macroscopic domain of solutions and which is/are part of the microscopic domain: boiling point elevatio
Juliette [100K]

Answer:

Macroscopic domain: Boiling point elevation, Henry's law, molarity, osmosis.

Microscopic domain: Hydrogen bond, ion-dipole attraction, nonelectrolyte, solvated ion.

Explanation:

A solution is composed of a solute (in high quantity) and one or more solute, which are dissolved in it. The properties of the solution can be characterized and measured in the macroscopic domain, or the microscopic domain when it's observed in the interactions with the molecules.

Boiling point elevation: It happens because the nonvolatile solvents interact with the solute, and so it will be difficult to boil it. The boiling point is a property of all the substance, and so, it can be noticed in the macroscopic domain.

Henry's law: States that the solubilization of a gas in a liquid depends on the partial pressure of the gas and by a proportional constant. Thus, the solubility of a gas is how much moles are dissolved in the volume of the solution, and so it's part of the macroscopic domain.

Hydrogen bond: It's an intermolecular interaction that happens in polar molecules that have bonds between hydrogen and a high electronegative element (N, O, or F). So, it's part of the microscopic domain.

Ion-dipole attraction: It's also an interaction that happens between an ion and a polar compound, so it's part of the microscopic domain.

Molarity: It represents how much moles of the solute is dissolved in the solution, so it's part of the macroscopic domain.

Nonelectrolyte: An electrolyte compound is the one which dissociates or ionizes, in the solvent, and because of that the solution can conduct electricity. A nonelectrolyte doesn't have this property. Because it depends on how the ions and molecules behave in solution, it's part of the microscopic domain.

Osmosis: Is the property of the solvent to go through a membrane from a side with fewer solutes (less concentrated) to another with more solute (high concentrated). So, it depends on the total amount of the solute, and so it's part of the macroscopic domain.

Solvated ion: A solvated ion is an ion that is surrounded by another ion, or by molecules, such water. So, it's part of the microscopic domain.

7 0
3 years ago
K = °C + 273 A 4.1 L sample of gas is held at 25 °C. If the gas expands to 6.8 L, what is the final temperature?
gregori [183]

Answer:

221 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 4.1 L

Initial temperature (T₁) = 25 °C

= 25 °C + 273

= 298 K

Final volume (V₂) = 6.8 L

Final temperature (T₂) =?

The final temperature of the gas can be obtained as follow:

V₁ / T₁ = V₂ / T₂

4.1 / 298 = 6.8 / T₂

Cross multiply

4.1 × T₂ = 298 × 6.8

4.1 × T₂ = 2026.4

Divide both side by 4.1

T₂ = 2026.4 / 4.1

T₂ ≈ 494 K

Finally, we shall convert 494 K to celcius temperature. This can be obtained as follow:

°C = K – 273

K = 494

°C = 494 – 273

°C = 221 °C

Thus the final temperature of the gas is 221 °C

6 0
3 years ago
Which statement below best describes the relationship of the reaction below?
timurjin [86]
For every two AB produced, the reaction requires three A
3 0
3 years ago
Read 2 more answers
Balance this equation-<br> Na3PO4 + KOH -&gt; NaOH + K3PO4
SSSSS [86.1K]
Na3PO4 + 3 KOH = 3 NaOH + K3PO4
3 0
3 years ago
Read 2 more answers
Pls help this is due in 10 minutes can someone tell me question 4
Veronika [31]

Answer:

Then the person will only have the dominant trait. There needs to be two recessive genes in order for that gene to appear.

Explanation:

5 0
3 years ago
Other questions:
  • How does the law of conservation of mass apply to this reaction: C2H4+3O2----&gt; 2H2O+2CO2
    10·2 answers
  • A combination of a heat engine driving a heat pump (see Fig. P7.106) takes waste energy at 50°C as a source Qw1 to the heat engi
    7·1 answer
  • Signs that say “do not use near an open flame” refer to a
    9·2 answers
  • Penn State Civil and Environmental Engineering Department just built a super-duper coal-fired power plant in Altoona, PA. It is
    5·1 answer
  • Debscribe each of the following with the correct term
    5·1 answer
  • Is the color In each pen the result of single dye or multiple dyes
    11·1 answer
  • What is the "major drawback" to using word equations?
    11·2 answers
  • What is the concentration of K+ ion in solution, in mmol/L?
    10·1 answer
  • What is waves is energy passing through the medium of water? true or false​
    11·2 answers
  • Select all the correct answers.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!