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Paladinen [302]
3 years ago
14

What is number 1 for b, c, and d?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
4 0
B because....................
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What is the mass number of oxygen atom with 7 neutrons?
kirill [66]
Oxygen has 8 protons
8 + 7 = 15
This isoptope is O-15
7 0
3 years ago
Why does every chemical reaction require a certain amount of activation energy?
Margaret [11]

Answer:

Forming the activated complex requires energy.

Explanation:

4 0
3 years ago
What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =
Lady bird [3.3K]

Answer:

4.86\times10^{-7}\ \text{m}

Explanation:

R = Rydberg constant = 1.09677583\times 10^7\ \text{m}^{-1}

n_1 = Principal quantum number of an energy level = 2

n_2 = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}

The wavelength of the light emitted is 4.86\times10^{-7}\ \text{m}.

6 0
3 years ago
Based on the following unbalanced reaction. how many moles of U can be 2 produced when you produce 3 moles of Z?
oee [108]

Answer:

9

Explanation:

3 0
2 years ago
It takes 412. KJ/mol to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrog
olga_2 [115]

Answer:

The maximum wavelength of light for which a carbon-hydrogen single bond could be broken by absorbing a single photon = 290 nm

Explanation:

                  So to break a single C - H bond require = \frac{412}{6.023 X (10)^{23} }

                           = 6.84 x 10⁻¹⁹ joule

Find the wavelength of a photon we use E = hν

                                                             ⇒    E = \frac{hc}{Wavelength}

                   Where h = Planck's constant = 6.626 x 10⁻³⁴ J.K⁻¹.Mole⁻¹

                               c = speed of light = 3 x 10⁸ m/sec

                                                           Wavelength = \frac{6.626 X 10^{-34} X 3 X 10^{8} }{6.84 X10^{-19}  }

                                                                                 = 2.9 x 10⁻⁷ m

                                                                                 = 290 nm

                                           ∵ 1 nm = 10⁻⁹ m

                         

7 0
3 years ago
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