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kati45 [8]
3 years ago
9

What can be the use of smoke transformed into liquid?

Chemistry
1 answer:
melisa1 [442]3 years ago
4 0

\huge\mathbb\red{ANSWER}

____________________________________

➡Liquid smoke is a water-soluble yellow to red liquid used for flavoring. It is used as a substitute for cooking with wood smoke while retaining a similar flavor. It can be used to flavor any meat or vegetable. It is generally made by condensing the smoke from wood, but can contain any number of food additives.

____________________________________

❤THANK YOU❤

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The density of pure gold (Au) is 19.3 g/cm3. What is the mass of a block of gold that measures 1.2 cm x 4.00 cm x 3.20 cm? Pleas
N76 [4]

Answer:

296.448 g

Explanation:

Density:

we know that density of an object can be measured by dividing its mass to its volume.

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m= mass

V= volume

Given data:

volume= 1.2 cm x 4.00 cm x 3.20 cm =15.36 cm3

density=  19.3 g/cm3

mass=?

Now we will put the values in the formula,

d=m/v

d x V= m

m = 15.36 cm3 x 19.3 g/cm3

m=296.448 g

so the mass of block of gold is 296.448 g

8 0
3 years ago
Which sound frequency with a human ear be able to detect? Select ALL correct answers.
Allisa [31]

Answer:

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5 0
3 years ago
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Why is it important for scientists to replicate each other’s experiments?
worty [1.4K]
They need to replicate the experiment to see if the found data is relaible and consistent. #TeamAlvaxic
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What is the overall cell potential for this redox reaction? Cd + Hg22+ → Cd2+ + 2Hg Given: Cd2+ + 2e− → Cd(s) = –0.40 and Hg22+
Hoochie [10]

Answer:  1.19 V

Explanation:

Standard potential for an electrochemical cell is given by:

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}

The E^0 values have to be reduction potentials.  

Given:

E^o_{Cd^{2+}/Cd}=-0.40V

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Cd+Hg_2^{2+}\rightarrow Cd^{2+}+2Hg

Cadmium is losing electrons , undergo oxidation and thus act as anode. mercury is gaining electrons, undergo reduction and thus acts as cathode.

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}=0.79-(-0.40)=1.19V

Thus the standard potential for an electrochemical cell with the cell reaction is 1.19 V.

4 0
3 years ago
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Which of the following cannotbe considered a single phase? a heterogeneous mixture a pure solid a homogeneous mixture a pure liq
MrRa [10]
A heterogeneous mixture cannot be considered a single phase
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