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kati45 [8]
3 years ago
9

What can be the use of smoke transformed into liquid?

Chemistry
1 answer:
melisa1 [442]3 years ago
4 0

\huge\mathbb\red{ANSWER}

____________________________________

➡Liquid smoke is a water-soluble yellow to red liquid used for flavoring. It is used as a substitute for cooking with wood smoke while retaining a similar flavor. It can be used to flavor any meat or vegetable. It is generally made by condensing the smoke from wood, but can contain any number of food additives.

____________________________________

❤THANK YOU❤

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Volume. Gases and liquids are typically measured in milliliters (mL) or cubic centimeters (cm^3) - both of which are equivalent (1 mL = 1 cm^3).
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For each equation , write all possible mole ratios . A. 2HgO(s)>2Hg(l)+O2(g) B. 4NH3(g)+6NO(g)>5N2(g)+6H2O(l)
Dafna11 [192]

A) For balanced chemical equation: 2HgO(s) → 2Hg(l) + O₂(g).

1) Mole ratio 1: n(HgO) : n(Hg) = 2 : 2 (1 : 1).

2) Mole ratio 2: n(HgO) : n(O₂) = 2 : 1.

3) Mole ratio 3: n(Hg) : n(O₂) = 2 : 1.

B) Balanced chemical equation: 4NH₃(g) + 6NO(g) → 5N₂(g) + 6H₂O(l).

1) Mole ratio 1: n(NH₃) : n(NO) = 4 : 6 (2 : 3).

2) Mole ratio 2: n(NH₃) : n(N₂) = 4 : 5.

3) Mole ratio 3: n(NH₃) : n(H₂O) = 4 : 6 (2 : 3).

4) Mole ratio 4: n(NO) : n(N₂) = 6 : 5.

5) Mole ratio 5: n(NO) : n(H₂O) = 6 : 6 (1 :1).

6) Mole ratio 6: n(N₂) : n(H₂O) = 5 : 6.

3 0
3 years ago
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Elemental Li and Na are prepared by electrolysis of a molten salt, whereas K, Rb, and Cs are prepared by chemical reduction.(c)
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2 years ago
1. Write the balanced equation for the breakdown of hydrogen peroxide. The equation has been written, you just have to balance.
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The balanced equation is attached in the image below. The coefficients are 2, 2, blank.

7 0
3 years ago
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Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570
Andrews [41]

x = 1.01

Explanation:

Given equation:

   y = 1.2345x – 0.6789

   y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

  Since we have been given y = 0.570

        y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

     since  y = 0.570

     0.57 = 1.2345x – 0.6789

    add 0.6789 to both sides;

 0.57 + 0.6789 =  1.2345x – 0.6789 + 0.6789

  1.2489‬ =   1.2345x

Divide both sides by  1.2345

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    x = 1.01

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7 0
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