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mart [117]
4 years ago
14

Bonds between metals and nonmetals tend to be ionic, but bonds between nonmetal atoms tend to be covalent. Explain why this is t

rue, using your understanding of electronegativity and ionization energy for these groups of elements.
Chemistry
2 answers:
Igoryamba4 years ago
5 0

Bond type depends on differences in electronegativity.


Metals and nonmetals tend to have large differences in electronegativity.


Nonmetals tend to have smaller differences in electronegativity.


Ionic bonds form between atoms that have large electronegativity differences.


Covalent bonds form between atoms with small electronegativity differences.

Assoli18 [71]4 years ago
3 0
Ionic bond is a type of bond in which one or more atoms are transferred to another atom which results to two ions with opposite charge. They attract each other.

The atom of another element is removed and then gained by another element which produces a noble gas electron configuration.

Covalent bond is a type of bond in which a pair or more electrons are being shared by the atoms of two elements.

Because of this, the molecules become stable by sharing the electrons thus creating a noble gas configuration for each of the atom.


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What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen? (5 points)
konstantin123 [22]
C3 H4 N1 ~~that’s what I think
8 0
3 years ago
: calculate the mass of the solute in 1.500 l of 0.30 m glucose, c6h12o6, used for intravenous injection
vfiekz [6]
Answer is: <span>the mass of the glucose is 81,07 grams.
</span>c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.
8 0
4 years ago
Consider the chemical equations shown here.
vichka [17]

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Now let us derive this equation:

Given equations:

   P₄_{s} + 30₂_{g}  ⇒ P₄0₆_{s}  equation 1;

   P₄_{s} + 50₂_{g} ⇒  P₄0₁₀_{s}  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆_{s} ⇒ P₄_{s} + 30₂_{g}   equation 3

                      +

            equation 2:

 P₄_{s} + 50₂_{g}  +    P₄0₆_{s}  ⇒  P₄0₁₀_{s}  +  P₄_{s} + 30₂_{g}  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

5 0
3 years ago
Calculate the molality of a solution prepared by dissolving 175 g of KNO3 in 750 g of water. (round to nearest hundreth)
Wittaler [7]
We will get the molality from this formula:
Molality = no.of moles of solute / Kg of solvent 

So first we need the no.of moles of KNO3 = the mass of KNO3 / molar mass of KNO3
no.of moles of KNO3 = 175 / 101.01 = 1.73 mol
By substitution in the molality formula:
∴ molality = 1.73 / (750/1000) = 2.3 Molal

6 0
3 years ago
Read 2 more answers
Select all steps below that you followed to practice laboratory safety during the experiment. used tongs or a test tube holder t
uysha [10]

Explanation:

Steps followed to practice laboratory safety during the experiment are as follows.

  • Used tongs or a test tube holder to hold materials over the Bunsen burner flame.
  • Wore gloves and goggles.
  • Made careful observations of the products and reactants.
  • Did not smell the gases produced.

When we heat a test tube over bunsen flame then the tube gets hot and when we hold it with bare hands then out hands will burn. Therefore, it is advised to hold test tube with the help of tongs or a holder so that our hands did not burn.

We should also wear gloves and goggles so that any acid would not spill directly on our hands, skin and eyes as it can affect or damage the skin severely.

Careful observations were made so that correct calculations about the experiment can be carried out.

It is also advised that we should not smell the gases produced but gases move freely from one place to another in a laboratory or any where else.

So, we can try to avoid it by covering our mouth with a cloth but we cannot stop it. If we keep on inhaling the gases produced in a laboratory then it can also lead to severe disease or defect in the human body.

8 0
3 years ago
Read 2 more answers
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