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mart [117]
3 years ago
14

Bonds between metals and nonmetals tend to be ionic, but bonds between nonmetal atoms tend to be covalent. Explain why this is t

rue, using your understanding of electronegativity and ionization energy for these groups of elements.
Chemistry
2 answers:
Igoryamba3 years ago
5 0

Bond type depends on differences in electronegativity.


Metals and nonmetals tend to have large differences in electronegativity.


Nonmetals tend to have smaller differences in electronegativity.


Ionic bonds form between atoms that have large electronegativity differences.


Covalent bonds form between atoms with small electronegativity differences.

Assoli18 [71]3 years ago
3 0
Ionic bond is a type of bond in which one or more atoms are transferred to another atom which results to two ions with opposite charge. They attract each other.

The atom of another element is removed and then gained by another element which produces a noble gas electron configuration.

Covalent bond is a type of bond in which a pair or more electrons are being shared by the atoms of two elements.

Because of this, the molecules become stable by sharing the electrons thus creating a noble gas configuration for each of the atom.


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A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
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4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
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Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

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Specific heat capacity of water = 1 cal/g.°C

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Formula:

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m = mass of given substance

c = specific heat capacity of substance

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ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

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