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sesenic [268]
3 years ago
11

A gas sample has an initial volume of 63.2 mL, an initial temperature of 42.0 ?C, and an initial pressure of 751 mmHg. The volum

e is decreased to 47.6 mL and the temperature is increased to 77.0 ?C.
Chemistry
1 answer:
exis [7]3 years ago
4 0

Answer:

Lets Write Down the Given Initial Conditions.

P_1 = 751mmHg           P_2 = --

V_1 = 63.2ml                V_2 = 47.6ml

T_1 = 42C                     T_2 = 77

In Order to Solve for the Unknown: P_2

we must use the Ideal Gas Law to Solve for the Second Unknown pressure:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Then Rearrange this equation in a form where P2 can be solved from:

P_2 = \frac{P_1V_1T_2}{T_1V_2}

Then Insert the Values from above to solve:

P_2 = \frac{(751 mmHg)(63.2ml)(77C)}{(47.6ml)(42C)}

The Answer is : 1830 mmHg considering sig figs

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3 0
3 years ago
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A student takes a sample of KOH solution and dilutes it with 100.00 mL of water. The student determines that the diluted solutio
Firlakuza [10]

Answer:

2.2mL

Explanation:

First, let us analyse what was given from the question:

C1 = 2.09M

V1 =?

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V2 =100mL

Using dilution formula (C1V1 = C2V2), we can calculate the volume of the original solution as follows:

C1V1 = C2V2

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Divide both side by the coefficient of V1 ie 2.09, we have:

V1 = (0.046 x 100) / 2.09

V1 = 2.2mL

8 0
3 years ago
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Natali [406]
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8 0
3 years ago
Which one of the atoms shown would be most likely to form a cation with a charge of 1?
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6 0
3 years ago
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If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul
bazaltina [42]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

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<span>
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<span>The correct answer is the first option. Pressure would increase. This can be seen from the equation above where V2 is indirectly proportional to P2.</span>

8 0
3 years ago
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