All categories

3 years ago

What is 3.008 +(-46) =

Mathematics

2 answers:

Serhud [2]3 years ago

5 0

-42.992 because take 3.008 from negative 42 and you get this

arsen [322]3 years ago

3 0

-42.992 because 3.008+(-46) is equal to -42.992

You might be interested in

The length of a rectangle is three more than its width. The perimeter is 86cm. Find the length and width of the rectangle. Write

elena-s [515]

P=2(l+w)
Substitute width plus 3 for length
Remember order of operations: multiply before adding

86=2((w+3) + w)
86=2w+6+2w
86=4w+6
80=4w
20=w
23=w+3=l

Check the answer
86=2((w+3) + w)
86=2((20+3)+20
86=2(23+20)
86=46+40
86=86

5 0

4 years ago

Write the ratio 42:24 in its simplest form.

slava [35]

Answer:

7:4

Step-by-step explanation:

42:24

divide both sides by 6

7:4

6 0

3 years ago

Read 2 more answers

Solve: 3.92 ÷ 0.07 (Answer as a decimal)

hjlf

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Water is leaking out of an inverted conical tank at a rate of at the same time that water is being pumped into the tank at a con

Alexus [3.1K]

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank

<h3><u>Answer:</u></h3>

The rate at which water is being pumped into the tank is 289,752 $cm^3/min$

<h3><u>Solution:</u></h3>

According to question,

There is an inverted conical tank, through which water is leaking at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate

<em><u>The dimension of tank are: </u></em>

Diameter = 4cm

Radius(r) = $\frac{diameter}{2}$ = 2cm

Height = 6cm

Clearly we can see that height is 3 times radius so, we can write

h = 3r OR r = h/3 ……………………. (1)

<em><u>The volume of cone "V" is given as:</u></em>

$\text { volume of cone }(\mathrm{V})=\frac{1}{3} \pi r^{2} h$ -------- (2)

From (1) and (2)

$\text { Volume of cone(V) }=\frac{1}{3} \pi\left(\frac{h}{3}\right)^{2} h$

$\mathrm{V}=\frac{\pi h^{3}}{27}$ -------- (3)

<em><u>Now we calculate the derivate:- </u></em>

$\frac{d V}{d t}=\frac{3 \pi h^{2}}{27} \frac{d h}{d t}$

$\frac{d V}{d t}=\frac{\pi h^{2}}{9} \frac{d h}{d t}$ --------- (4)

According to question, when height is 2m = 200cm, the water level is rising at a rate of 20 cm/min

$\frac{d h}{d t}=20 \mathrm{cm} / \mathrm{min}$

On putting above values in equation(4) and solving we get

$\frac{d V}{d t}=279252$

Hence, the rate at which water is being pumped is 289,752 $cm^3/min$ which is the sum of water volume increasing at rate of 279,252 and 10,500 leaking out

3 0

4 years ago

What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m? (Please sh

Ivan

We have been given the measure of two parallel sides as 11 m and 5 m. And we are given one of the slanted sides as 4 m.

From the given information, we can find the base of one of the side triangles as 3 m.

Therefore, upon using Pythagorean theorem, we get the set up for height as

$h^{2}=4^{2}-3^{2}=7$