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KiRa [710]
4 years ago
12

The center of the Milky Way most likely contains

Physics
1 answer:
Naya [18.7K]4 years ago
3 0

Answer:

The center of the Milky Way most likely contains a supermassive black hole.

Explanation:

Because it is  an eleptical galaxy, it has a little rotation to it but not enough to flatten out so the center will contain a supermassive black hole.

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action and reaction are equal in magnitude and opposite in direction then , why do not they balance each other​
Galina-37 [17]

Explanation:

Newton’s third law of motion states that every action has an equal and opposite reaction. This indicates that forces always act in pairs. Reaction forces are equal and opposite, but they are not balanced forces because they act on different objects so they don’t cancel each other out.

5 0
3 years ago
List the color of the stars from hottest to coldest
masha68 [24]
Blue, blue-white, Yellow-white, yellow, yellow-orange, and red. Hope this helps.
8 0
3 years ago
What is frequency? <br><br> (P.S. please help)
kvasek [131]

Explanation:

the rate at which something occurs or is repeated over a particular period of time or in a given sample

4 0
3 years ago
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Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes th
Airida [17]
F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2

That is one answer.

Also, you can use the fact that N = kg*m/s^2

[G] = kg * m / s^2 * m^2 / kg^2 = m^3 /(s^2 * kg)
5 0
3 years ago
A slingshot is used to launch a stone horizontally from the top of a 20.0 meter cliff. The stone lands 36.0 meters away.
alisha [4.7K]
A) 

     It is a launch oblique, therefore the initial velocity in the vertical direction is zero. Space Hourly Equation in vertical, we have:

S=S_{o}+v_{o}t+ \frac{at^2}{2} \\ 20= \frac{10t^2}{2} \\ t=2s
 
     Through Definition of Velocity, comes:

\Delta v=  \frac{\Delta S}{\Delta t}  \\ v_x= \frac{36}{2}  \\ \boxed {v_{x}=18m/s}


B)
 
     Using the Velocity Hourly Equation in vertical direction, we have:

v_{y}=v_{y_{o}}+gt \\ v_{y}=10\times2 \\ \boxed {v_{y}=20m/s}
  
     The angle of impact is given by:

cos(\theta) =\frac{v_{x}}{v_{y}}  \\ cos(\theta) = \frac{18}{20}  \\ cos(\theta) =0.9 \\ arccos(0.9)=\theta \\ \boxed {\theta \approx 25.84}


If you notice any mistake in my english, please let me know, because i am not native.

7 0
3 years ago
Read 2 more answers
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