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krok68 [10]
2 years ago
13

Determine the atomic number, atomic mass and element name of the following:

Chemistry
1 answer:
laiz [17]2 years ago
3 0

Answer:

Carbon-14

Carbon-14: with 6 protons and 8 neutrons, and an atomic mass of 14.

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Un tanque de acetileno para una antorcha de soldadura de oxiacetileno proporciona 9340 L de gas acetileno, C2H2, a 0°C y 1 atm 2
Helen [10]

Answer:

3.33 tanques de O₂

Explanation:

Basados en la reacción:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

<em>2 moles de acetileno reaccionan con 5 moles de oxígeno produciendo 4 moles de dióxido de carbono y 2 moles de agua</em>

<em />

La ley de Avogadro dice que el volumen de un gas bajo temperatura y presión constantes es proporcional a las moles de este gas. Así, como 2 moles de acetileno reaccionan con 5 moles de oxígeno, los litros de O₂ necesarios para quemar 9340L de acetileno son:

9340 L C₂H₂ × (5 moles O₂ / 2 moles C₂H₂) = <em>23350L de O₂</em>

Si un tanque contiene 7x10³ L de O₂ serán necesarios:

23350L O₂ ₓ (1 tanque / 7x10³L) =<em> 3.33 tanques de O₂</em>

6 0
3 years ago
A substance that can be separated into two or more substances only by a chemical change is
Yuliya22 [10]
<span>A substance that can be separated into two or more substances only by a chemical change is </span><span>known as a </span><span>heterogeneous</span><span> mixture</span>
5 0
3 years ago
3.01 × 1023 molecules H2O
grandymaker [24]
3079.23 is what you get when you multiply the answers.
6 0
3 years ago
Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has
bija089 [108]
<h2>Answer:</h2>

Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic  \: mass }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 72 \times84.9 + 28 \times 87  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 6112.8 + 2436  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 8548.8  }{100} \\

\footnotesize \longrightarrow \:  \bf Average \:  atomic  \: mass =  85.488 \: amu  \\

8 0
2 years ago
What are the standard ways to make a solution of known concentration? (select all that apply.)?
MatroZZZ [7]

1- Molar solutions: based on number of moles of chemical in 1 litre of solution

2- Weight % solution:  the weight of chemical divided by the total weight of the solution (chemical + water) and multiplied by 100.

8 0
3 years ago
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