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2 years ago

8

you drop a marble ball into a glass filled with water, which results ib 3.75 mL of water being displaced (spilled out). given th

at the mass of the marble ball is 9.513g, what is the density of that marble ball?

1 answer:

erica [24]2 years ago

7 0

Answer:- Density is 2.54 gram per mL.

Solution:- $density=\frac{mass}{volume}$

Mass of the marble ball is given as 9.513 g and it's volume is 3.75 mL.

To calculate the density of the marble ball let's plug in the values in the formula:

$density=\frac{9.513g}{3.75mL}$

$density=2.54\frac{g}{mL}$

So, the density of the marble ball is 2.54 gram per mL.

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Match the following chemical reactions:

S_A_V [24]

Answer:

Synthesis - 4

reversible- 2

exchange- 1

decomposition-3

Explanation:

In synthesis reaction two or more components combines to form a single product. example 2H2+O2⇒2H2O

In reversible reaction two reactants combine to form two products . The products then reacts and forms back the reactants. example N2 +3H2 ⇒2NH3

In exchange reaction there is an alternation of ions of reactants to form new products. AB+CD ⇒AC + BD

In decomposition reaction, molecules of a compound break down by the action of heat or light or catalyst. example CaCO3 ⇒CaO +CO2

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2 years ago

Calculate the number of C atoms in 0.190 mole C6H14O.<br> can anyone help me on this one?

likoan [24]

In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6* $10^{23}$ (atoms of C in one mole) = 6.84* $10^{23}$ atoms.

8 0

3 years ago

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro

melamori03 [73]

<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For nickel:</u>

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol$

For the given chemical reaction:

$3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)$

<u>For nickel (II) oxide:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from $\frac{3}{3}\times 0.252=0.252mol$ of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

$0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g$

<u>For aluminium:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from $\frac{2}{3}\times 0.252=0.168mol$ of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

$0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g$

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

4 0

3 years ago

An FM radio station broadcasts electromagnetic radiation at a frequency of 103.4 MHz (megahertz; MHz =106sâ€“1). Calculate the w

kap26 [50]

Answer:

$Wavelength=2.899\ m$

Explanation:

The relation between frequency and wavelength is shown below as:

$c=frequency\times Wavelength$

c is the speed of light having value $2.998\times 10^8\ m/s$

Given, Frequency = 103.4 MHz = $103.4\times 10^{6}\ Hz$ ( as 1 MHz = 10⁶ Hz)

Thus, Wavelength is:

$Wavelength=\frac{c}{Frequency}$

$Wavelength=\frac{2.998\times 10^8}{103.4\times 10^{6}}\ m$

$Wavelength=2.899\ m$

5 0

3 years ago

When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _

olya-2409 [2.1K]

Balancing redox reactions:

Oxygen should be balanced by adding $H_{2}O$ as needed, while hydrogen should be balanced by adding $H^{+}$ .

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding $H_{2}O$ , $H^{+}$ , and $e^{-}$ in that order, each reaction is brought into equilibrium:

By putting the right number of water ( $H_{2}O$ ) molecules on the other side of the equation, the oxygen atoms are brought into balance.
By adding $H^{+}$ ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
Total the fees for each side. Add enough electrons ( $e^{-}$ ) to the more positive side to make them equal. (As a general rule, $e^{-}$ and $H^{+}$ are nearly always on the same side.)
The $e^{-}$ on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
Now that the equation has been verified, it can be balanced.

Learn more about redox reaction here,

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7 0

2 years ago