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Wittaler [7]
3 years ago
8

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres w

ith masses of 1.40 kg and 14.0 g whose centers are separated by about 2.30 cm. Calculate the gravitational force between these spheres, treating each as a particle located at the center of the sphere.
Physics
2 answers:
Pepsi [2]3 years ago
8 0

Answer:

The gravitational force F =2.47*10⁻⁹N

Explanation:

Given Data;

First mass m1 = 1.40kg

Second mass m2 = 14.0g = 14/1000 = 0.014kg

distance (r) = 2.30cm = 0.023m

Gravitational constant = 6.67* 10⁻¹¹N/m²kg²

gravitational force (F)?

For calculating the gravitational force, we use the formula;

F = (Gm₁m₂)/r²

Substituting into the formula, we have

F = (6.67 * 10⁻¹¹ * 1.40 * 0.014)/0.023²

   = 1.30732*10⁻¹²/5.29*10⁻⁴

   = 2.47*10⁻⁹N

NeTakaya3 years ago
6 0

Answer:

F=2.47*10^{-10} N

Explanation:

The gravitational force is calculated by using

F=G\frac{M_1M_2}{r^2}

G: Cavendish constant = 6.67*10^{-12}Nm^2/kg^2

r=2.30cm=0.023m

M1=1.4kg

M2=14.0g=0.014kg

By replacing we have

F=2.47*10^{-10} N

hope this helps!!

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For the heater coil in the problem, we know V=220 V and R=220 \Omega, therefore we can rearrange Ohm's law to find the current through the device:
I= \frac{V}{R}= \frac{220 V}{220 \Omega}=1 A

(B) The resistance of a conductive wire depends on three factors. In fact, it is given by:
R= \rho \frac{L}{A}
where
\rho is the resistivity of the material of the wire
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Basically, we see that the longer the wire, the larger its resistance; and the larger the section of the wire, the smaller its resistance.
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3 years ago
there is only one basic format for a professional report. a. audience b. All of these should be considered when deciding on a re
Anna007 [38]

Answer:

The answer is letter b. All of these should be considered when deciding on a report format.

Explanation:

A Professional Report is a type of formal document about a topic or information that is intended for a specific audience or purpose. The report's style of writing needs a lot of knowledge from the writer. Oftentimes, it involves the following important elements: <em>Title, Summary, Body, Discussion, Conclusion and Recommendation. </em>

The writer should write according to his target audience and purpose. He also needs to consider the length of his report, as well as the suitable words and sentences that he should use.

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5 0
3 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
A gas is compressed at a constant pressure of 0.800 atm from 12.00 L to 3.00 L. In the process, 390 J of energy leaves the gas b
Andru [333]

Answer:

a)W= - 720 J

b)ΔU= 330 J

Explanation:

Given that

P = 0.8 atm

We know that 1 atm = 100 KPa

P = 80 KPa

V₁ = 12 L = 0.012 m³       ( 1000 L = 1 m³)

V₂ = 3 L = 0.003 m³

Q= - 390 J ( heat is leaving from the system )

We know that work done by gas given as

W = P (V₂ -V₁ )

W= 80 x ( 0.003 - 0.012 ) KJ

W= - 0.72 KJ

W= - 720 J    ( Negative sign indicates work done on the gas)

From first law of thermodynamics

Q = W + ΔU

ΔU=Change in the internal energy

Now by putting the values

- 390 = - 720 + ΔU

ΔU= 720 - 390  J

ΔU= 330 J

5 0
3 years ago
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