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enot [183]
3 years ago
13

Someone help me... The following numbers are given: 17, 25, 35, 43, 55, 119, 187. Choose four numbers from the given numbers and

write them in the boxes of 2×2 grid so that the numbers in the neighbor boxes are not co-prime and the numbers in non-neighbor boxes are co-prime. (Note that the neighbor boxes are those which share a side).

Mathematics
1 answer:
Drupady [299]3 years ago
6 0

Step-by-step explanation:

Co-prime numbers are numbers that only have 1 as a common factor.

For example, 35 = 1×5×7, and 39 = 1×3×13.  So 35 and 39 are co-prime.

Write the prime factorization of each number:

17 = 1×17

25 = 1×5²

35 = 1×5×7

43 = 1×43

55 = 1×5×11

119 = 1×7×17

187 = 1×11×17

43 is co-prime with all of these, so we will not use it.

If we start with 35 in the upper left, and 187 in the lower right, then we can also rule out 17 and 25, since these are co-prime with either 35 or 187.

So that leaves 55 and 119 as the other two numbers.  They can go in any order, as long as they are diagonal from each other.

\left[\begin{array}{cc}35&55\\119&187\end{array}\right]

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Veronica has been saving dimes and quarters she has 110 coins in all and the total value is 18.50 how many dimes and quarters do
Lady_Fox [76]

This problem can be solved by the chicken rabbits method or you can just do simple algebra.

I.) Chicken and rabbits method

First assume all 110 coins are dimes and none are quarters.

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Now for each dime we switch out for a quarter, we adds 15 cents to the total value.

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So we have 50 quarters.

That first method is very good and very quick once you get the hang of it, now I'm going to show you the algebraic way to solve this.

Let's say there are x dimes and y quarters.

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Now we set the numbers of quarters to y so the answer is 50 quarters.

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3 years ago
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ANSWER : A


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